The standard enthalpy of formation for NaCl solid is: -411,12 kJ/mol at 25 0C.
Moles of NaCl=6*3=18mol Mass needed=[35.5+23]*18=1053g
These compounds react forming a white insoluble precipitate - silver chloride: NaCl + AgNO3 = AgCl + NaNO3
Sodium chloride is a compound forming large lattices.
first nothing seems to happend, but minutes later a sedimentation or deposit of nacl will be clearly seen. this nacl will be forming on the sorrounding of the recipient were you heat up the solution
The enthalpy of dissolution of NaCl in water is the amount of heat energy released or absorbed when NaCl dissolves in water.
We first calculate the amount, in moles, of NaCl that we will need.Amount of NaCl needed = 0.24 x 400/100 = 0.096mol. Mass of NaCl needed = (23.0 + 35.5) x 0.096 = 5.616g So to produce 400ml of 0.24M NaCl solution, accurately add 5.616 grams of NaCl to 400ml of deionised water.
Sodium chloride is a solid but NaCl can be dissolved in water forming a solution.
Sodium chloride is a polar salt with ionic bonds, forming crystalline lattices.
m (molality)=moles of solute/kg of solvent To calculate moles of solute you convert 292.5 g of NaCl to moles of NaCl. So (292.5gNaCl)(1mole NaCl / 58.4gNaCl)= 5.0085 moles NaCl Now plug and chug. 0.25m=5.0085moles NaCl / x x=5.0085 moles NaCl /.25m x=20kg
I think it is a chemical change Forming underground it is a chemical change Salt forming from a saline solution for example h20 + NaCl --delta-> h2 + O2 + NaCl (This is not a balanced solution) This is a physical change, since there is no change to the Sodium Chloride
If your solution is a total of 414g and 3.06% of it needs to be NaCl, then you just take 414 x .0306 = grams of NaCl. The rest of the grams will be from other species in the solution.
If you think to lattice energy the value is 789 kJ/mol.