Moles of NaCl=6*3=18mol Mass needed=[35.5+23]*18=1053g
117 grams of sodium chloride (NaCl) is equivalent to 117 grams of chlorine gas because each molecule of NaCl contains one sodium atom and one chlorine atom.
The answer is 26,3 g.
If your solution is a total of 414g and 3.06% of it needs to be NaCl, then you just take 414 x .0306 = grams of NaCl. The rest of the grams will be from other species in the solution.
Since the reaction involves the formation of sodium chloride (NaCl), the molar ratio of sodium to chlorine is 1:1. Therefore, if 10 grams of sodium reacts to form 35 grams of NaCl, then 35 grams of chlorine is also needed for this reaction.
The answer is 0,9 g pure, dried NaCl.
The Molecular Weight of NaCl = 58.5 So to make 1L of 4M NaCl solution you need 4*58.5=234g of NaCl So to make 100mL of the above solution you need 23.4 grams of NaCl
To calculate the grams of NaCl needed, you first need to determine the molar mass of NaCl (58.44 g/mol). For a 0.25M solution, you would need 0.25 moles of NaCl in 1 liter (since Molarity = moles/volume). So, you would need 14.61 grams of NaCl (0.25 mol/L * 58.44 g/mol).
You need 841,536 g NaCl.
It depends how strong a solution you want to make. The molecular mass of NaCl is 58.44, so for a 1 molar solution you would dissolve 58.44 grams in water and make the volume up to 1 litre. For a 0.1 mol solution you'd take 5.844g to a litre, and a 2 mol solution you'd take 116.88g to a litre of water.
The answer is 8 g NaCl.
The number of formula units of NaCl is 11335.10e17.
The needed mass of sodium chloride is 29,22 g.