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How many grams of KI are required to prepare 500ml of 0.04 M KI?
To calculate the grams of KI required, use the formula: grams = molarity (M) × volume (L) × molar mass (g/mol). The molarity is 0.04 M and the volume is 0.5 L (500 ml). The molar mass of KI is approximately 166 g/mol. Therefore, grams of KI required = 0.04 M × 0.5 L × 166 g/mol = 3.32 grams.
How do you prapare 0.01 m potassium permanganate?
To prepare a 0.01 M solution of potassium permanganate (KMnO4), first calculate the amount needed by using the formula: mass (g) = molarity (mol/L) × volume (L) × molar mass (g/mol). The molar mass of KMnO4 is approximately 158.04 g/mol, so for 1 liter of solution, you would need 1.58 grams of KMnO4. Dissolve this amount in a small volume of distilled water, then transfer the solution to a 1-liter volumetric flask and dilute to the mark with distilled water. Mix thoroughly to ensure complete dissolution.
What actors and actresses appeared in Leo Mol in Light and Shadow - 1994?
The cast of Leo Mol in Light and Shadow - 1994 includes: Leo Mol as Leo Mol
What nicknames does Ann Li go by?
Ann Li goes by Ann.
When did Li Si die?
Li Mian died in 788.
What is the percent composition of Li in LiOH?
The molar mass of LiOH is 23.95 g/mol for Li, 15.999 g/mol for O, and 1.008 g/mol for H. The molar mass of LiOH is 23.95 + 15.999 + 1.008 = 40.957 g/mol. Therefore, the percent composition of Li in LiOH is (23.95/40.957) x 100 = 58.44%.
How many moles of Li atoms are in 10.56grams of Li?
How many lithium atoms are in 10.56 g of lithium
What is the molar mass of lithium oxide li20?
The chemical formula for lithium oxide is ( \text{Li}2\text{O} ), not ( \text{Li}{20} ). To calculate the molar mass of lithium oxide, you add the molar masses of its components: lithium (Li) has a molar mass of about 6.94 g/mol, and oxygen (O) has a molar mass of about 16.00 g/mol. Thus, the molar mass of ( \text{Li}_2\text{O} ) is ( 2 \times 6.94 , \text{g/mol} + 16.00 , \text{g/mol} = 29.88 , \text{g/mol} ).
What is the number of moles of 27.6 g of lithium (li)?
3.977 mol
Molar mass of Li?
The molar mass of Li = 6.941 g/mol
How much would 5.0 moles of lithium weigh in gram?
5.0 mol Li * 6.941 g/mol Li = 34.705 = 35 g Lithium
What is the mass of 21.3 mol Li?
To find the mass of 21.3 moles of lithium (Li), you can use the molar mass of lithium, which is approximately 6.94 g/mol. Multiply the number of moles by the molar mass: (21.3 , \text{mol} \times 6.94 , \text{g/mol} = 147.58 , \text{g}). Therefore, the mass of 21.3 moles of lithium is approximately 147.58 grams.
What is the molar mass of lithium oxide Li2O?
Lithium has a molar mass of 6.94 g/mol. Oxygen has a molar mass of 16.00 g/mol. Since Lithium Oxide has 2 Lithium atoms, the molar mass is: (6.94 x 2) + 16.00 = 29.88 g/mol.
What is the amount in moles in each elemental sample 11.8 g Ar 3.55 g Zn 26.1 g Ta 0.211 g Li?
To find the number of moles in each elemental sample, we use the formula: moles = mass (g) / molar mass (g/mol). Argon (Ar): ( \text{molar mass} = 39.95 , \text{g/mol} ), so ( \text{moles} = 11.8 , \text{g} / 39.95 , \text{g/mol} \approx 0.295 , \text{mol} ). Zinc (Zn): ( \text{molar mass} = 65.38 , \text{g/mol} ), so ( \text{moles} = 3.55 , \text{g} / 65.38 , \text{g/mol} \approx 0.0543 , \text{mol} ). Tantalum (Ta): ( \text{molar mass} = 180.95 , \text{g/mol} ), so ( \text{moles} = 26.1 , \text{g} / 180.95 , \text{g/mol} \approx 0.144 , \text{mol} ). Lithium (Li): ( \text{molar mass} = 6.94 , \text{g/mol} ), so ( \text{moles} = 0.211 , \text{g} / 6.94 , \text{g/mol} \approx 0.0304 , \text{mol} ).
What is the atomic mass of Li?
The atomic mass of Li, which stands for lithium, is approximately 6.94 atomic mass units (u).
5 What mass of lithium is required to react completely with 60.00mL of nitrogen gas at STP in?
To determine the mass of lithium required to react with nitrogen gas, we first need to calculate the amount of nitrogen gas present using the ideal gas law. Then, we can use the stoichiometry of the balanced chemical equation between lithium and nitrogen to find the mass of lithium needed for complete reaction according to the molar ratio in the balanced equation.
How many moles are there in 9.4 g of NaOH?
To find the number of moles in 9.4 g of NaOH, you first need to calculate the molar mass of NaOH (22.99 g/mol for Na, 15.999 g/mol for O, and 1.008 g/mol for H). Add these together to get 39.997 g/mol for NaOH. Next, divide the given mass by the molar mass to get the number of moles: 9.4 g / 39.997 g/mol ≈ 0.235 moles of NaOH.
