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1.4 g

*convert g to mol*

Pb=207.2 amu (Atomic Mass)

Cl=35.453 amu (atomic mass)

since it's PbCl2, 207.2 + 35.453 + 35.453=278.106

1.4/278.106=.005 mol

*use Avogadro's number to find formula units*

.005 x 6.02E10^23 --> 3.03E10^22 formula units PbCl2

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Q: How many formula units are in 1.4 g of PbCl2?
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