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How many joules of energy does it take to heat 1 kilogram water 5 degrees?
Wiki User
∙ 15y ago
Q = mcΔT Q = (1000 g)(4.18 J/(g*K))(5 K) Q = 20900 J Q = 20.9 kJ
Wiki User
∙ 15y ago
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How many joules of energy are released when 45.0 g of water cools from 18.0 oC to 7.0 oC?
energy = mass x specific heat x temperature change = 45 x 4.181 x 11 J = 2069.595 J
One kilocalorie of heat energy will raise temp of water how many degrees celsius?
Change in temperature, dT,=1/m, where m is the amount of water, in kilograms. Depends on how much kilograms of water you have. The equation to use is Q=cm(dT), where c is the specific heat capacity of water (conventional use puts it 4186 J/(kg*C degrees)), m is the mass, in kilograms, of the water you're heating, dT is the amount of degrees, in Celsius (or Kelvin), that you want to heat the water by, and Q is the amount of energy needed, in Joules. 1 kilocalorie equals 4186J, solving for change in temperature (dT), dT=Q/(cm). Substituting in Q and c gives you dT=1/m. If you do not know the mass, but only volume, m=pV, where p is the density of water (convetionally 1 *10^3 kg/m^3) and V is the volume of the amount of water you have in m^3.
What energy unit is defined as the heat required to raise on kilogram of water by one degree Celsius?
I believe it is Calorie.
How much heat energy is required to raise the temperature of 15 g of water 25 degrees Celsius?
6480 calories8LBs X 15 gallons x 54 DEGREES = 6480 CALORIES
What has more thermal energy one gram of water at 75 degrees or 100 grams of water at 75 degrees?
(75'C)x(1g) < (75'C)x(100g) .'. The second option has more thermal energy.
Energy of?
The most common unit of energy in Biology is calories. A calorie is a unit of energy, require to raise 1 kilogram of water to 4.1868 joules.
How many joules of energy are required to raise the temperature of 74g of water from 20 degrees to 70 degrees celsius?
15480.80
What is an amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy?
The amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy is 42,2g H2O.
Does it it take more energy to heat the water to 100 degrees celsius or boil it?
If by "boil" you mean have it all evaporate, that takes MUCH more energy. For example, to increase the temperature of one gram of water from 20 to 100 degrees Celsius, you need 4.2 joules/gram/degree times 80 degrees = about 336 joules; then, to evaporate all the water, you need an additional 2257 joules.
How much energy is required to heat 955 g of water from 20 degrees C to 100 degrees C?
4.1858 joules of energy will raise the temperature of 1 g of water by 1oC. Thus, 4.1858 * 955 * 80 = 319795.12 joules of energy is required to raise the temperature of 955 g of water by 1oC.
How much energy was transferred to the water of 1.3 kg of water equals from 20 degrees to 100 degrees c?
1.3 kg water = 1300 grams. q(Joules-heat energy) = mass * specific heat * change in temperature q = (1300 g)(4.180 J/gC)(100 C - 20 C) = 4.3 X 105 Joules of heat energy ========================
What is the unit of measurement of energy needed to heat one kilogram of water by 2 degrees F?
It is a calorie
What is the potential energy of a 8 million kg water falling at 50meters?
Each kilogram of water has 50 joules of gravitational potential energy at the top,and 50 joules of kinetic energy when it hits the bottom.For 8 million of them, that adds up to 400,000,000 joules(in each position).The formula for potential energy is mgh - mass x gravity x height. The above calculation didn't take into consideration the gravity - a factor of about 9.8.
How much heat in joules is needed to raise the temperature of 4.0 L of water from 0 degrees Celsius to 70.0 degrees Celsius?
It takes 4.186 Joules to heat one gram of water by 1-degree Celsius. 4.186 * 4000 = 16,744 Joules to heat 4 kilos of water by 1-degree. 16,744 * 70 = 1,172,080 Joules. The above assumes that one litre of water weighs exactly 1 Kilogram.
How many joules of heat energy must be supplied to 21 g of water to raise the temperature of the water from 24 to 95 degrees Celsius?
21 grams through 71 degrees is 21x71 calories.
How much heat is required to convert 0.3 kilogram of at 0 degrees C to water at the same temperature?
Measured in joules, the process would take 334,584 J to occur completely.
What energy unit is defined as the heat required to raise one kilogram of water by one degrees celsius?
I believe it is Calorie.
