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694 mL of glucose solution 0,2 M are needed.

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8y ago
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8y ago

moles glucose needed = 25.0 g x 1mol/186 g = 0.139 moles
voluem of 0.2 M needed: (x L)(0.2 mol/L) = 0.139 moles
x = 0.694 L = 694 mls

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8y ago

30 ml 50% dextrose + 70 ml water

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10y ago

25

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4y ago

25

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Q: How many ml of 50 percent dextrose solution are needed to obtain 25 g of dextrose?
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