You are missing a measurement to obtain volume. A height it going to be needed.
BY adding excess Filter off excess MgCO3(s) . heat the filter to get a saturated solution , cool to obtain crystals , filter . H2SO4(aq)+MgCO3(s)--->MgSO4(aq)+H2CO3(g)
pure
When you use your senses to obtain information, you are making an observation. This is a major part of science where you use your senses or the readings of instruments to directly acquire information from a primary source.
Thermionic emission
To prepare 100 ml of a 5% dextrose solution from a 50% dextrose solution, you would use the formula: C1V1 = C2V2. You will need 10 ml of the 50% solution (C1) and dilute it with 90 ml of water (V1) to obtain the desired 100 ml of 5% dextrose solution.
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution. How much of the 20 percent solution did the pharmacist use in the mixture (in liters).
10
25 gallons
10 liters.
If the percents given are by weight or mass, this is very straightforward: The ratio between the desired percentage and the initial percentage is 1/50. Therefore, a given mass of initial solution must be diluted to 50 times its original mass to obtain the desired lower concentration, or in other words, 49 parts of diluent must be mixed with each part of initial solution. If the percents involve volume measurements, it would be necessary to take into account and change in density occasioned by the dilution.
4 litres
50 gallons @ 3% must be added.
40.8 grams
To determine the amount of 18% solution to add: Let x = volume of 18% solution to be added. 0.18x + 0.10(360) = 0.15(x + 360) Solving for x, you would need to add 75 ml of the 18% solution to the 360 ml of 10% solution to obtain a 15% solution.
0.6 of a pint.
75% of the water, I would assume.