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C6H6 is the molecule of benzene and it's molecular weight is 78, calculated as
6 x 12 +6 x 1=78
and you will understand it if you know some basics of chemistry.
then,
You know that each mole of a molecule weighs exactly those number of grams as much as is its molecular weight. That means if a molecule has 'M' as its molecular weight, then one mole of it weighs exactly M grams when actually weighed using a weighing machine.
This means one mole of benzene weighs 78 grams. then 195 grams of C6H6 has (1/78)x195 moles or 195/78 moles in it.
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How many grams of C6H6 are present in 12.7 moles of C6H6?
Molar mass C6H6 = 12.0x6 + 1.00x6 = 72 + 6 = 78 g/mole12.7 moles x 78 g/mole = 990.6 grams = 991 g (to 3 significant figures)
How many moles of MgCl2 are there in 313 g of the compound?
Approx 3.29 moles.
If 2Ag2O and 4Ag o2 then if you started with 3.25 moles of Ag2O how many moles of O2 would be produced?
what is ag2o
How can you convert from molecules to grams?
How many molecules are in 94 grams of sodium fluoride
How many moles in 5 grams of NaCl?
For this you need the atomic mass of Na. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.11.5 grams Na / (23.0 grams) = .500 moles Na
How many moles of carbon atoms can be obtained from the decomposition of C6H6 in a 1.68 moles sample?
10.08 moles (there are six carbon atoms per molecule of C6H6, hence, six times the number of moles of carbon can be produced).
How many grams of C6H6 are present in 12.7 moles of C6H6?
Molar mass C6H6 = 12.0x6 + 1.00x6 = 72 + 6 = 78 g/mole12.7 moles x 78 g/mole = 990.6 grams = 991 g (to 3 significant figures)
How many moles of C6H6 should be completely combusted in order to produce 0.4000 moles of carbon dioxide?
0.06667 moles
How many moles of hydrogen atoms are present in 2 moles of benzene?
2 moles of benzene gives 12 moles of hydrogen atoms since benzene is C6H6
How many moles of benzene (C6H6) should be completely combusted in order to produce 0.4000 mol of carbon dioxide?
By using conversion of units: Benzene = C6H6 4.5 mol C x (1 mol Benzene / 6 mol C) = .75 mol Benzene
How many moles of CO2 are produced when 45.0g of C6H6 react completely in the following equation 2C6H6 plus 15O2 12CO2 plus 6H2O?
2C6H6 + 15O2 ==> 12CO2 + 6H2Omoles C6H6 combusted = 45.0 g x 1 mole/78 g = 0.577 molesmoles CO2 formed = 0.577 moles C6H6 x 12 moles CO2/2 moles C6H6 = 3.46 moles CO2
How many moles of ZnCl2 will be produced from 23.0 g of Zn?
Atomic mass from my Periodic Table for Zinc is 65.38. This means 1 mole of naturally occurring zinc has a mass of 65.38 grams. If your zinc sample is pure zinc then: (mass of your sample)/(65.38 grams) = # moles of zinc.
Calculate the molality of a solution of 44.9 grams of C10H8 in 175 grams of C6H6?
Molality = moles of solute / kg of solvent solute = 44.9 grams of C10H8. There are approx 128 g/mole in C10H8. 44.9 grams x 1/128 moles/gram = 0.351 moles (approx) convert 175 grams C6H6 into 0.175 kilograms Molality = 0.351 moles solute (or C10H8) / 0.175 kg solvent (C6H6) Answer is 2.00 Molal
How many grams of NH3 will have the same number of molecules at 15.0 g of C6H6?
You first need to find the mass weight of NH3. wt. of N + (wt. of H)= 14.0067 + 3(1.0067)= 17.03052 Now that you have the mass weight, you divide 15 into 17.03052... 15.0/17.03052 = 0.8807 moles in 15. g of NH3
How many moles of O2 are needed to burn 1.50 moles of C8H18?
Balance this combustion reaction first! 2C4H10 + 13O2 -> 8CO2 + 10H2O 0.86 moles C4H10 (13 moles O2/2 moles C4H10) = 5.6 moles of oxygen required ----------------------------------------
How do you Calculate the number of moles in 17.2 g of benzene?
17.2 (g) / 78.11 (g.mol−1) = 0.2202 = 0.220 mole C6H6
How many protons are in C6H6?
1
