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C6H6 is the molecule of benzene and it's molecular weight is 78, calculated as
6 x 12 +6 x 1=78
and you will understand it if you know some basics of chemistry.
then,
You know that each mole of a molecule weighs exactly those number of grams as much as is its molecular weight. That means if a molecule has 'M' as its molecular weight, then one mole of it weighs exactly M grams when actually weighed using a weighing machine.
This means one mole of benzene weighs 78 grams. then 195 grams of C6H6 has (1/78)x195 moles or 195/78 moles in it.
What else can I help you with?
How many grams of C6H6 are present in 12.7 moles of C6H6?
Molar mass C6H6 = 12.0x6 + 1.00x6 = 72 + 6 = 78 g/mole12.7 moles x 78 g/mole = 990.6 grams = 991 g (to 3 significant figures)
How many moles of MgCl2 are there in 313 g of the compound?
Approx 3.29 moles.
If 2Ag2O and 4Ag o2 then if you started with 3.25 moles of Ag2O how many moles of O2 would be produced?
what is ag2o
How can you convert from molecules to grams?
Multiply the number of moles by the molecular weight.
How many moles in 5 grams of NaCl?
For this you need the atomic mass of Na. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.11.5 grams Na / (23.0 grams) = .500 moles Na
How many moles of C6H6 should be completely combusted in order to produce 0.4000 moles of carbon dioxide?
1 mole of C6H6 produces 6 moles of CO2 during combustion. Therefore, 0.4000 moles of CO2 would require (0.4000 moles CO2) / (6 moles C6H6 per mole CO2) = 0.0667 moles of C6H6 to be completely combusted.
How many moles of carbon atoms can be obtained from the decomposition of C6H6 in a 1.68 moles sample?
Each molecule of C6H6 contains 6 carbon atoms, so when 1 mole of C6H6 decomposes, 6 moles of carbon atoms are obtained. Therefore, in a 1.68 mole sample of C6H6, 6 × 1.68 = 10.08 moles of carbon atoms can be obtained from the decomposition.
How many grams of C6H6 are present in 12.7 moles of C6H6?
Molar mass C6H6 = 12.0x6 + 1.00x6 = 72 + 6 = 78 g/mole12.7 moles x 78 g/mole = 990.6 grams = 991 g (to 3 significant figures)
What is the molality of a solution of 75.2 g AgClO4 dissolved in 885 g C6H6?
To calculate molality, we first need to find the moles of AgClO4 and the moles of solvent, C6H6. Calculate moles of AgClO4: 75.2 g / molar mass of AgClO4 Calculate moles of C6H6: 885 g / molar mass of C6H6 Then, molality (m) = moles of solute / kg of solvent. Divide the moles of AgClO4 by the kg of C6H6 to find the molality of the solution.
A solution contains 72.0 g of HCl and 468 g of (C6H6). What is the mole fraction of benzene?
First, calculate the moles of each component: moles of HCl = 72.0 g / molar mass of HCl and moles of C6H6 = 468 g / molar mass of C6H6. Then, calculate the total moles in the solution by adding the moles of each component. Finally, calculate the mole fraction of benzene by dividing the moles of C6H6 by the total moles in the solution.
How many moles of hydrogen atoms are present in 2 moles of benzene?
2 moles of benzene gives 12 moles of hydrogen atoms since benzene is C6H6
How many moles of benzene (C6H6) should be completely combusted in order to produce 0.4000 mol of carbon dioxide?
To completely combust benzene (C6H6), 15 moles of oxygen are used for every 1 mole of benzene. This reaction produces 6 moles of carbon dioxide for every 1 mole of benzene. Therefore, 0.4000 mol of carbon dioxide would require (0.4000 mol)(1 mol C6H6/6 mol CO2)(15 mol O2/1 mol C6H6) = 1.5 moles of benzene to be combusted.
How many moles of CO2 are produced when 45.0g of C6H6 react completely in the following equation 2C6H6 plus 15O2 12CO2 plus 6H2O?
2C6H6 + 15O2 ==> 12CO2 + 6H2Omoles C6H6 combusted = 45.0 g x 1 mole/78 g = 0.577 molesmoles CO2 formed = 0.577 moles C6H6 x 12 moles CO2/2 moles C6H6 = 3.46 moles CO2
How many moles of ZnCl2 will be produced from 23.0 g of Zn?
Atomic mass from my Periodic Table for Zinc is 65.38. This means 1 mole of naturally occurring zinc has a mass of 65.38 grams. If your zinc sample is pure zinc then: (mass of your sample)/(65.38 grams) = # moles of zinc.
Calculate the molality of a solution of 44.9 grams of C10H8 in 175 grams of C6H6?
Molality = moles of solute / kg of solvent solute = 44.9 grams of C10H8. There are approx 128 g/mole in C10H8. 44.9 grams x 1/128 moles/gram = 0.351 moles (approx) convert 175 grams C6H6 into 0.175 kilograms Molality = 0.351 moles solute (or C10H8) / 0.175 kg solvent (C6H6) Answer is 2.00 Molal
How do you Calculate the number of moles in 17.2 g of benzene?
To calculate the number of moles in 17.2 g of benzene, divide the given mass by the molar mass of benzene. The molar mass of benzene (C6H6) is approximately 78.11 g/mol. Therefore, 17.2 g ÷ 78.11 g/mol ≈ 0.22 moles of benzene.
How many grams of NH3 will have the same number of molecules at 15.0 g of C6H6?
You first need to find the mass weight of NH3. wt. of N + (wt. of H)= 14.0067 + 3(1.0067)= 17.03052 Now that you have the mass weight, you divide 15 into 17.03052... 15.0/17.03052 = 0.8807 moles in 15. g of NH3
