25.4 g (I2) / 254 (g/mol I2) = 0.100 (mol I2)
Melting heat = Evaporization heat:
This is because of sublimation, Iodine's Triple point (T=113°C, p=12.1 kPa)
is lower than its Melting point (113.7 °C, 100kPa).
∆Hsub(298K) = 62.42kJ/mol
Sublimation heat needed = 0.100 (mol I2) *62.42 kJ/mol = 6.24 kJ
They must gather close together until they can't bunch anymore and then they start to melt because they ran out of space.
When energy is provided to any substance and its bonds are loosened, it starts melting.
It requires energy to melt ice, converting it into water. This energy is recovered (returned to the environment) when the water freezes. Therefore, it is convenient to think of the water as storing this energy, while it is in the liquid state.
It will melt! But you have to add enough energy to equal the latent heat as well as to bring the ice up to the freezing point, if it is in a freezer to start it will be at about -21degC.
Thermal energy is a product of two variables; the temperature, and the mass. If two objects having the same mass were heated to the same temperature, they would have the same thermal energy. If an object weighing ten grams was heated to 1000º C, it would have less thermal energy than an object weighing 2 tons, heated to 100º C. To demonstrate this, imagine the amounts of ice each of the above objects could melt.
To calculate the energy needed to melt 25.4 grams of I2 (iodine), you can use the formula: energy = mass x heat of fusion. The heat of fusion for iodine is 15.52 kJ/mol. First, find the molar mass of I2 (253.8 g/mol) and then convert the mass to moles. Finally, multiply the moles by the heat of fusion to get the energy needed.
This is a trick question because "I2" is the chemical symbol for MOLECULAR iodine (your question did not say melt Iodine, it said melt I2).Only gaseous iodine is composed of I2 molecules and as it is a gas it CAN NOT melt.
The energy needed to melt a substance is given by its heat of fusion. For L's, this value is typically around 334 J/g. So, to melt 25.4 grams of L's, you would need 25.4 grams x 334 J/g ≈ 8476 J of energy.
The energy required to melt a substance is its heat of fusion. For Palladium (Pd), the heat of fusion is 16.74 kJ/mol. To calculate the energy needed to melt 4.24 grams of Pd, first convert to moles by dividing by the molar mass of Pd (106.42 g/mol), then multiply by the heat of fusion. This yields approximately 3.34 kJ of energy needed to melt 4.24 grams of Pd.
To melt 1 gram of ice at 0°C, it requires 334 joules of energy. So for g grams of ice, the energy needed would be g multiplied by 334 joules.
The energy required to melt a substance can be calculated using the heat of fusion value for that substance. The heat of fusion for palladium (Pd) is 16.74 kJ/mol. To convert grams to moles, divide the given mass by the molar mass of Pd (106.42 g/mol), then multiply by the heat of fusion value to find the energy needed to melt 4.24 grams of Pd.
To calculate this, we can use the formula: energy needed = mass * heat of fusion. The heat of fusion for ice is 334 J/g. Thus, the energy needed to melt 5 grams of ice is 5 grams * 334 J/g = 1670 Joules.
The specific latent heat/ latent heat of fusion of ice is 333.55 J/gtherefore by using the equation E=mLE = 54 * 333.55= 18011.7 JTherefore the energy needed to melt 54 grams of ice at its melting point which is keeping it at 0 degrees Celsius is 18011.7 Joules.
To melt 10 grams of ice at 0 degrees Celsius, it would require 80 calories of heat energy per gram, so a total of 800 calories (80 calories/gram * 10 grams = 800 calories) would be needed.
80 calories per gram (called the latent heat of fusion) 80 x 255.67 = 20453.6 calories
Grams solid mol/g Hfusion
It takes approximately 64,000 Joules of energy to melt 1kg of gold. Therefore, to melt 2kg of gold, you would need around 128,000 Joules of energy.