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25.4 g (I2) / 254 (g/mol I2) = 0.100 (mol I2)

Melting heat = Evaporization heat:

This is because of sublimation, Iodine's Triple point (T=113°C, p=12.1 kPa)

is lower than its Melting point (113.7 °C, 100kPa).

∆Hsub(298K) = 62.42kJ/mol

Sublimation heat needed = 0.100 (mol I2) *62.42 kJ/mol = 6.24 kJ

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13y ago
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12y ago

Type your answer here... idk

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7y ago

The energy needed is 1,84 kJ/mol.

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6y ago

The needed energy is 1,55 kJ.

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12y ago

1.57x10^3

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Q: How much energy is needed to melt 25.4 grams of iodine?
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