yes
Pseudo means "false" so pseudoscience is something claiming to be science that isn't. And science is ability to produce solutions in some problem domain
It is something that is not testable, whereas science is!
Only an old pseudoscience (Gall, 1796).
its a solid state.
a insoluable solid is a solid that can not be disolved
1 mole CaF2 = 78.074g CaF2 0.06mol CaF2 x 78.074g CaF2/mol CaF2 = 5g CaF2 (rounded to 1 significant figure)
Pseudo solid is a term used to describe a material that behaves as solid in some respects but exhibits characteristics of a liquid in others. For example, certain gels and colloids can display pseudo solid behavior, where they can flow like liquids but still maintain some structural integrity like solids.
The name for the ionic compound CaF2 is calcium fluoride.
Calcium fluoride (CaF2) is sparingly soluble in water due to its strong ionic bond between the calcium and fluoride ions. When CaF2 is placed in water, the ions dissociate and interact with the polar water molecules, which helps break the ionic bond and allows CaF2 to dissolve in water. However, CaF2 has low solubility in water because the attraction between the ions in the solid state is strong compared to the interactions with water molecules.
Of these choices:a. Ca(s) + F2(g) → CaF2(s)b. Ca(g) + F2(g) → CaF2(s)c. Ca2+(g) + 2F−(g) → CaF2(s)d. Ca(g) + 2F(g) → CaF2(s)
The scientific name for fluorite is calcium fluoride (CaF2).
CaF2.
No, CaF2 is an ionic compound. Ionic compounds are typically formed between a metal (like calcium) and a non-metal (like fluorine), resulting in the transfer of electrons from the metal to the non-metal to form ions. In the case of CaF2, calcium (Ca) is a metal and fluorine (F) is a non-metal.
In one molecule of CaF2, there is one calcium atom and two fluorine atoms.
The solubility of CaF2 in water increases with temperature. At 25C, the solubility of CaF2 in water is about 0.0016 g/100 mL. As the temperature rises, the solubility also increases.
To find the grams of F in 165 g of CaF2, you need to consider the molar mass of CaF2. Calcium (Ca) has a molar mass of about 40.1 g/mol, and fluorine (F) has a molar mass of about 19 g/mol. So, the molar mass of CaF2 is about 40.1 + (19 x 2) = 78.1 g/mol. Then, you can calculate the grams of F in 165 g of CaF2 by determining the proportion of F in the compound CaF2 compared to its total molar mass.
The coefficient for F2 in the chemical equation Ca + F2 → CaF2 is 1.