No. The product of (wavelength) times (frequency) of an electromagnetic wave is
always the same number ... the speed of the wave. So if one of those quantities
increases, then the other one must decrease by the same factor, in order for the
product to remain constant.
The speed of a wave doesn't depend on its frequency.REASON:According to the formulaV=frequency * Lambdaso,V/ Lambda= frequencyHere,Frequency is inversely proportional to the wavelength. so, If we increase the value of frequency then by same amount frequency will decrease and will cancel out the effect of each other the "V" will remain constant.
In theory, they can remain unchanged for their entire existence. However, in practise, nature isn't so nice and evolution happens eventually.
When two or more substances are combined so each substance can be separated by physical means the result is a mixture. An example is dissolving salt in water. By boiling off all the water, the salt will remain.
The factors that are kept the same in an experiment are the constants.The factors that aren't kept the same in an experiment are the variables.
Your damages and insurance premium remain.
When wavelength decreases, frequency increases, and when wavelength increases, frequency decreases. The product of (wavelength) times (frequency) is always the same number ... the speed of the wave. So when one of them changes, the other one must change in the opposite direction in order for their product to remain unchanged.
The product of (wavelength) x (frequency) of any wave phenomenon is alwaysthe same number ... the speed of the wave. So if wavelength changes, thenfrequency must change by exactly the same factor in the opposite direction,in order for their product to remain constant.
I believe that the speed will remain constant, and the new wavelength will be half of the original wavelength. Speed = (frequency) x (wavelength). This depends on the method used to increase the frequency. If the tension on the string is increased while maintaining the same length (like tuning up a guitar string), then the speed will increase, rather than the wavelength.
Because the product of (frequency times wavelength) is always the same number ... it's the speed of the wave. So if one of them changes, the other one has to change in the opposite direction, in order for the product to remain the same number.
Because the product of (frequency times wavelength) is always the same number ... it's the speed of the wave. So if one of them changes, the other one has to change in the opposite direction, in order for the product to remain the same number.
Because the product of (frequency times wavelength) is always the same number ... it's the speed of the wave. So if one of them changes, the other one has to change in the opposite direction, in order for the product to remain the same number.
More energy would be transferred in the wave, so a sound wave would get louder and a light wave would get brighter. The wavespeed, frequency, and wavelength of the wave will remain the same.
The product of (wavelength) times (frequency) is always the same number ... the speed of the wave. So if either of them changes, the other one changes by exactly the same factor in the other direction, in order for the product to remain coinstant.
Will not ever happen. Wavelength and frequency are each others reciprocals. Frequency divided into 1 equals its' wavelength and visa versa. It would speed up. EM waves do a maximum of 'c' in the interstellar medium 'vacuum' but slow down in more dense media. ie. from 186,200 to a little less in the atmosphere, to 140,000 in water, less still in glass, and down to virtually zero in Bose-Einstein Condensate. On leaving water, if the wavelength were to remain constant the frequency and thus velocity would increase. i.e. the rule in the previous answer is only correct for any one given medium. Out of interest this fact actually disproves an original assumption behind SR, as EM wave speed in the vacuum is 'absolute' with respect to the medium.
The speed of a wave doesn't depend on its frequency.REASON:According to the formulaV=frequency * Lambdaso,V/ Lambda= frequencyHere,Frequency is inversely proportional to the wavelength. so, If we increase the value of frequency then by same amount frequency will decrease and will cancel out the effect of each other the "V" will remain constant.
The frequency of the light remains unchanged as it depends on the source of the light rather than the medium its traveling in.
Because the product of (frequency times wavelength) is always the same number ... it's the speed of the wave. So if one of them changes, the other one has to change in the opposite direction, in order for the product to remain the same number.