To solve this question we would need to know if you are adding or subtracting. Unless the equation is set up to equal 360 then the equation has no rationale answer.
(x2 - 9) / (x2 + 3) does not have a simple solution. Perhaps the question you were actually looking to have answered was:(x2 - 9) / (x + 3)Which is equal to (x - 3). This is called a difference of squares, where any time you see a term in the format:(x2 - b2)You know that it is equal to (x + b)(x - b). Of course, (x + b)(x - b) / (x + b) will be equal to (x - b), giving you the answer above.If on the other hand, you are indeed looking for the answer to (x2 - 9) / (x2 + 3), you could try long division. That will give you 1 with a remainder of negative twelve, or:1 + 12/(x2 + 3)Alternately, if you have a value for the term, you can solve the equation:(x2 - 9) / (x + 3) = ax2 - 9 = ax + 3ax2 - ax = 9 + 3ax2 - ax + (a/2)2 = 9 + 3a + (a/2)2 ← this is called "completing the square".(x - (a/2))2 = 9 + 3a + (a/2)2x - (a/2) = [9 + 3a + (a/2)2]1/2x = [9 + 3a + (a/2)2]1/2 + a/2You can then plug in whatever value is given for 'a'. For example, if it's equal to zero:x = [9 + 3(0) + (0/2)2]1/2 + 0/2x = (9 + 0 + 0)1/2 + 0x = 91/2x = 3Note that x can not be equal to negative three, as that would cause division by zero in the original equation.
The use of pythagoras theorem helps out here. Make it a right angled triangle. x2 = 152 + 102. X2 is 225 + 100 = 325. Square root of 325 is 18.03 metres
If measure angle 3 = x2 + 4x and measure angle 5 = 3x + 72, find the possible measures of angle 3 and angle 5
Greek letters such as delta are often used in different contexts. One use that is often given to delta is to indicate the difference between two values. Thus, delta-x can be the same as x2 - x1, where "x2" and "x1" are the values of "x" at different points in time, for example.
Ka = ([H+][A-])/[HA]) Let concentration of dissociated acrylic acid be x. 0.000056 = (x2)/(0.10 - x) Rearrange: 0.0000056 - 0.000056x - x2 = 0 x = 0.002339 Therefore: [H+] = 0.002339 M pH = -log[H+] = 2.63 Percent dissociation: 0.002339/0.10 = 0.02339 = 2.34 %
x2 + 13x = -30 ∴ x2 + 13x + 30 = 0 ∴ (x + 3)(x + 10) = 0 ∴ x ∈ {-3, -10}
x2-13x+36=(x-9)(x-4)=0 x=9 or x=4
11+2 = 13 and 2*11 = 22 So: x2+13x+22 = (x+2)(x+11) when factored
x = +13x = - 13
x2 + 13x + 12 = (x + 1)(x + 12)
x2 + 13x + 36 = (x + 9)(x + 4)
42 + x2 = 13x ∴ x2 - 13x + 42 = 0 ∴ (x - 6)(x - 7) = 0 ∴ x ∈ {6, 7}
This is a quadratic equation question which will have two answers: 2x2+42 = x2+13x 2x2-x2-13x+42 = 0 x2-13x+42 = 0 Factorising the equation gives you: (x-6)(x-7) = 0 Therefore: x = 6 or x = 7
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x2 - 13x = 0x (x - 13) = 0x = 0andx = 13
x2 + 13x + 36 = 0 so (x+4)(x+9) = 0 so that x = -4 or x = -9
-x2 - 11x + 26= -x2 - 13x + 2x + 26= (2x - x2) + (26 - 13x)= x(2 - x) + 13(2 - x)= (2 - x)(x + 13)