combination reaction
Balanced Formula:2Mg + O2 --> 2MgOMole ratio:2 : 1 : 2Givens:.486 g oxygen.738 g magnesium24.3 g = atomic mass of magnesium16.0 g = atomic mass of oxygen40.3 g = molecular mass of magnesium oxideFind the amount (in moles) of Magnesium oxide that oneelement will make:(.486 g O) / (16.0 g O) × (2 moles MgO)= .0608 moles MgO(.783 g Mg) / (24.3 g Mg) = .0322 moles MgOThere is less MgO produced with magnesium than oxygen; therefore, magnesium is the limiting reactant and the oxygen is the excess reactant. The magnesium determines how much Magnesium oxide is produced. It would be good to get .0608 moles of MgO, but there isn't enough magnesium. So the amount of MgO produced will be determined on the amount of Magnesium.Convert moles of MgO produced with the amount of oxygen to grams:.0322 mol MgO (40.3 g) = 1.30 grams of MgO produced--------------------------------------------------------------------------------------------------------You will need 3 moles of oxygen if you start with six moles of magnesium. This will allow you to produce 6 moles of magnesium oxide.Source: (e2020)
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4Na+O2=2Na2O? That must be the equation... Im not sure what you're asking... But, in a combustion reaction, something reacts with oxygen gas (O2). In this equation sodium is reacting with oxygen... So, yes, this is a combustion reaction.
KOH is the reactant in this reaction:2 MnO2 + 4 KOH + O2 = 2 K2MnO4 + 2 H2O
The question is a little vague, but rust could be categorised under chemistry as rust is a chemical reaction between oxygen (O2) and water (H2O)
The reaction is between Mg and O2. 2Mg+O2->2MgO
The chemical reaction is:2 Mg + O2 = 2 MgO
I'm not entirely sure but an unbalanced equation is: Mg + O2 -----> MgO
Oxidation reaction 2Mg + O2 ----------- 2MgO
2Mg + O2 --------> 2MgO
There are two atoms of oxygen on each side.
This compound is the magnesium oxide, MgO.
This chemical reaction is:2 Mg + O2 = 2 MgO
Mg+O2----->MgO
The reaction is: 2 Mg + O2 = 2 MgO
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The reaction is:2 Mg + O2 = 2 MgO