combination reaction
Balanced Formula:2Mg + O2 --> 2MgOMole ratio:2 : 1 : 2Givens:.486 g oxygen.738 g magnesium24.3 g = atomic mass of magnesium16.0 g = atomic mass of oxygen40.3 g = molecular mass of magnesium oxideFind the amount (in moles) of Magnesium oxide that oneelement will make:(.486 g O) / (16.0 g O) × (2 moles MgO)= .0608 moles MgO(.783 g Mg) / (24.3 g Mg) = .0322 moles MgOThere is less MgO produced with magnesium than oxygen; therefore, magnesium is the limiting reactant and the oxygen is the excess reactant. The magnesium determines how much Magnesium oxide is produced. It would be good to get .0608 moles of MgO, but there isn't enough magnesium. So the amount of MgO produced will be determined on the amount of Magnesium.Convert moles of MgO produced with the amount of oxygen to grams:.0322 mol MgO (40.3 g) = 1.30 grams of MgO produced--------------------------------------------------------------------------------------------------------You will need 3 moles of oxygen if you start with six moles of magnesium. This will allow you to produce 6 moles of magnesium oxide.Source: (e2020)
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4Na+O2=2Na2O? That must be the equation... Im not sure what you're asking... But, in a combustion reaction, something reacts with oxygen gas (O2). In this equation sodium is reacting with oxygen... So, yes, this is a combustion reaction.
KOH is the reactant in this reaction:2 MnO2 + 4 KOH + O2 = 2 K2MnO4 + 2 H2O
The question is a little vague, but rust could be categorised under chemistry as rust is a chemical reaction between oxygen (O2) and water (H2O)
This compound is the magnesium oxide, MgO.
I'm not entirely sure but an unbalanced equation is: Mg + O2 -----> MgO
The reaction is between Mg and O2. 2Mg+O2->2MgO
There are two atoms of oxygen on each side.
The symbol equation for the reaction of magnesium with oxygen to form magnesium oxide is: 2Mg + O2 -> 2MgO
2Mg + O2 --------> 2MgO
The balanced chemical equation for the reaction is: 2 Mg + O2 → 2 MgO. This means that for every 1 mole of O2, 2 moles of MgO are produced. Therefore, if 0.200 mol of O2 reacts completely, it will produce 0.400 mol of MgO.
The reaction 2 Mg + O2 -> 2 MgO is indeed a combustion reaction, where magnesium (Mg) reacts with oxygen (O2) to produce magnesium oxide (MgO). Combustion reactions are characterized by rapid reactions with oxygen, resulting in the release of energy in the form of heat and light. In this case, magnesium undergoes combustion to form magnesium oxide.
When magnesium (Mg) reacts with oxygen (O2), a vigorous exothermic reaction occurs, producing magnesium oxide (MgO) as the product. The magnesium metal undergoes oxidation, forming a white powdery residue of magnesium oxide. The reaction is accompanied by a bright white light as the magnesium burns in the presence of oxygen.
Balanced Equation: 2Mg(NO3)2 = 2MgO + 4NO2 + O2
Oxidation reaction 2Mg + O2 ----------- 2MgO
The reaction : Mg + O2-----------> MgO The balanced reaction : 2 Mg + O2-----------> 2 MgO that is 2 moles of Mg reacts with one mole of oxygen gas. moles of Mg reacted = 12 g / 24 g mol-1=0.5 mol. Thus the no. of mol of O2 reacted = 0.5 mol /2 =0.25 mol If the gas is at standard temperature and pressure, then Volume of 1 mol of O2 gas = 22.4 dm3 Volume of 0.25 mol of O2 gas = 22.4 x 0.25 dm3= 5.6 dm3 the volume of oxygen that will be used to react completely with 12 g Mg =5.6 dm3 (provided that the gas is at the standard conditions.)