The needed heat is:
Q = 10 x 20 x 0,031 = 6,2 calories
specific heat is the amount of heat to be absorbed required to raise a substance 1 degree celsius. And by heat being absorbed, i mean energy, because specific heat is measured in joules
1 calorie (or rather, kilocalorie). This is because the specific heat of water is 1.
We know that Q=m.s.t, where Q= Heat, s= Specific heat of the substance, t=temperature(Difference in temperatures) =>s= Q/m.t =>s=525/(25X15) =>s=525/375 =>s=1.4 cal/g/0c Specific heat of the substance is 1.4 cal/g/0c.
The amount of heat a substance can hold.
Another term used for specific heat is temperature.
change in temperature does not effect specific heat. for example,specific heat of water is 4.14 j/g.k at any temperature
the formula to find specific heat is specific heat= calories/mass X change in temperature.
specific heat(; your welcome!
specific heat(; your welcome!
If you can measure 3 of these 4 things then you can use this formula q( energy in Joules ) = Mass * specific heat * temperature final - temperature initial
Every substance has a specific heat. The definition of specific heat is: The amount of energy, usually measured in calories, needed to raise the temperature of one gram of a certain substance by one degree Celsius.
q (amt of heat) = mass * specific heat * temp. differenceThe specific heat of water is 1.00 cal/goC & the temperature difference is 70-30 = 40oCq = (105 grams)*(1.00 cal/goC)*(40oC)= 4,200 calories
' J ' means Joules , unit for the amount of Energy in Physical Science... Heating Effect of Current ... Joule's Constant = Electrical Energy in Joules / Amount of Heat in calories Electrical Energy in Joules = Voltage in volts x Current in amperes x Time in seconds Amount of Heat in calories = Mass of Water x Specific Heat of Water x Change in Temperature of Water + Mass of Calorimeter x Specific Heat of Calorimeter x Change in Temperature of Calorimeter ANSWER: The Amount of Heat will be very hot and Joule's Constant will be too big which will make it not realistic as part of the experimental calculations. You must know that it is necessary to get the temperature in the state of equilibrium. Remember that, due to the use of the metal stirrer which absorbed the heat energy, the temperature of water inside the calorimeter had decreased partially or was delayed in rising up despite to the fact that the electrical energy generated is proportionally equal to the increase in temperature of the calorimeter.
use the equation q=mc∆t, where q is the calories required, m is mass, c is specific heat capacity and ∆t is the change in temperature. Therefore... q=(40g)(0.06 cal/g◦c)(88c - 20c) q=163.2 calories
488.25 J/kg/*C
0.11cal/g degrees C
Yes- to be more specific they are "emulsified" by bile, before it is absorbed.