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You need the volume of the solution and the stoiciometric coefficients. You must first find the moles of the first substance, by multiplying the molarity (M) by the volume (L). Once you have moles, you can compare the two substances by looking at the coefficients in your chemical equation. For instance, if your chemical equation is: HCl + NaOH --> H2O + NaCl you have a 1:1 ratio. Therefore the moles of HCl = the moles of NaOH however if you have 2H2O --> 2H2 + O2 the ratio of H2O to O2 is 2:1; the moles of H2O = 2 x the moles of O2
This is an incomplete question for several reasons. Iron bromide can be FeBr2 or FeBr3 and this will influence the answer. Also, in order to precipitate silver bromide, one would add silver nitrate, but it isn't stated how much silver nitrate is used. Assuming FeBr2 is used, and there is excess AgNO3, then .... 2AgNO3 + FeBr2 ----> 2AgBr(s) + Fe(NO3) moles FeBr2 = 2.96 g x 1 mol/216 g = 0.0137 moles moles AgBr produced = 2 x 0.0137 = 0.0274 moles mass AgBr produced = 0.0274 moles x 188 g/mole = 5.15 grams <---answer
There are 23 atoms in 6.0 g of water. Using this formula (6 g H2O)(1 mol H2O / 18 g H2O) = 1/3 mol H2O (1/3 mol H2O)(2 mol H / 1 mol H2O)(6.022 x 10^23 atoms H / 1 mol H) = 4.0 x 10 therefore 23 atoms.
1 mole of substance contains 6.02 x 1023 of its constituent particles. Accordingly, there would be 5.85 moles (of the substance) in a sample containing 3.52 x 1024 particles.
The amount of moles in a molecule:1 molecule * 1 mole/6.022 x 1023 molecules = 1.66 x 10-24 molesDoes everyone have general chemistry tests this week?yes
0.943 moles H2O (6.022 X 1023/1 mole H2O) = 5.68 X 1023 molecules of water ========================
The value is 1,328.10e-3 moles.
There are 1.204 x 10^24 water molecules in two moles of water. This is because one mole of anything contains Avogadro's number of particles, which is 6.022 x 10^23. Thus, two moles of water would have twice that number of molecules.
To calculate the number of molecules in 2.81g of H2O, you first need to convert grams to moles using the molar mass of water (18.015 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. The calculation would be: 2.81g H2O / 18.015 g/mol = 0.156 moles H2O; 0.156 moles H2O x 6.022 x 10^23 molecules/mol = 9.40 x 10^22 molecules of H2O.
1 mole H2O = 18.015g H2O 1.57mol H2O x 18.015g H2O/1mol H2O = 28.3g H2O
5 moles H2O (1 mole O/1 mole H2O)(6.022 X 1023/1 mole O)(1 mole O atoms/6.022 X 1023)= 5 moles oxygen atoms=================( as you see this is a formal set up that you do not need to use fully as Avogadro's number is over itself as a form of one )5 moles H2O (2 moles H/1 mole H2O)6.022 X 1023/1 mole H)(1 mole H atoms/6.022 X 1023)= 10 moles hydrogen atoms====================
Using the molar mass of nh3, we find that we have 2.5 moles of nh3. Since 3 moles of h2o are produced per 2 moles of nh3, we see that we will produce 3.75 moles of h2o. This is equivalent to around 3.79 g.
Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O
The molar mass of water (H2O) is approximately 18.015 g/mol. To find the mass of 3.2 moles of water, you multiply the number of moles by the molar mass: 3.2 moles x 18.015 g/mol = 57.648 g. So, the mass of 3.2 moles of water is approximately 57.648 grams.
To find the number of moles in 3.612 × 10^24 molecules of H2O, divide the number of molecules by Avogadro's number, which is approximately 6.022 × 10^23 molecules/mol. 3.612 × 10^24 molecules / 6.022 × 10^23 molecules/mol ≈ 6 moles of H2O.
In 1 mole of water (H2O), there are 2 moles of hydrogen (H). This means that in 2.08 moles of water, there are 2.08 x 2 = 4.16 moles of hydrogen. To convert moles to grams, we use the molar mass of hydrogen: 4.16 moles x 1.01 g/mol = 4.22 grams of hydrogen.
First write down the BALANCED reaction eq'n. Octane + oxygen = Water + Carbon Dioxide. 2CH3(CH2)6CH3 + 25O2 = 18H2O + 16CO2 The molar ratios are 2:25 :: 18:16 So '2' moles of octane produces 18 moles of water. So by equivlance 0.468 : x :: 2 : 18 Algebraically rearrgange x = (0.468/2) X 18 => x = 0.234 x 18 = > x = 4.212 moles water produces.