This question can't be answered if you don't provide the chemical reaction's equation with this other data.
No, it does not. The volume of water changes according with it's temperature. Water, unlike other substances, it has a minimum volume at 4 degrees Celsius.
crystalline structures that tend to collapse when 0 degrees celsiurs in increased. The melting of these crystals further decreases the volume of the water. The water undergoes two processes at the same time- contraction and expansion. Volume tends to decrease as ice crystals collapse, while volume tends to increase due to great molecular motion
1,400 mL
It's most dense at 4 degrees celsius. Get any lower and it takes up more volume. As a general rule, chemicals get denser as they get colder.
With the ideal gas law PV=nRT, if n (number of molecules, R(gas constant) and T (temperature) are fixed, then the product of P (pressure) and V (volume) is also constant. So. Pressure and Volume are inversely related. If pressure goes up, volume must go down and if pressure goes down, volume must increase. The same goes with increasing or decreasing volume.
468ml
The volume (at 20 degrees celsius and a pressure of 1 atmosphere) is 107.7mL. Both changes in temperature or pressure will change the answer.
136.73 mL
By decreasing the pressure with the volume kept constant.
By decreasing the pressure with the volume kept constant.
A fixed quantity of gas at a constant pressure exhibits a temperature of 27 degrees Celsius and occupies a volume of 10.0 L. Use Charles's law to calculate: the temperature of the gas in degrees Celsius in atmospheres if the volume is increased to 16.0 L
A sample of Ar gas occupies a volume of 1.2 L at 125°C and a pressure of 1.0 atm. Determine the temperature, in degrees Celsius, at which the volume of the gas would be 1.0 L at the same pressure.
1 mL
The melting temperature of a substance is dependent upon the pressure and specific volume. The melting temperature of liquid at standard pressure of 1atm (~100kPa) is 0 degrees Celsius.
25 ml. The volume would not change. Now pressure on the other hand...
P1V1/T1 = P2V2/T2Assuming only temperature and volume are changing and pressure will be kept constant:V1/T1 = V2/T2Only Kelvin can be usedV1/273 = V2/523Assume the volume at 0 ºC is 1 unit thenV2 = 1.92 units
P1V1/T1 = P2V2/T2Assuming only temperature and volume are changing and pressure will be kept constant:V1/T1 = V2/T2Only Kelvin can be usedV1/273 = V2/523Assume the volume at 0 ºC is 1 unit thenV2 = 1.92 units