It's hard to understand what you're trying to ask. There could be multiple reasons why you aren't getting the correct voltage, ranging from testing for DC when you should be testing for AC to accidentally measuring the RMS value. Most likely, however, is that you're not measuring with a balanced, three phase load. Tri-phasic power works by splitting the voltage into three separate sin waves that are phase shifted by 120 degrees in relation to each other. Therefore one stays a normal sin wave, one becomes a sin wave phase shifted to 120 degrees, and the other phase shifts to -120 degrees. This means that at any given instantaneous time the average voltage between them is approximately the value of the DC offset. This is only true if you're measuring them with a balanced three phase load, however. If you measure one line at a time, you're going to get erroneous answers. You need to measure tri-phasic power with a balanced three phase load.
V/R = I meaning, Voltage (in volts) divided by Resistance (in Ohms) equals Current (in Amperes, a.k.a. Amps
Each phase supplies 15 kVA. The primary has a line-to-neutral voltage of 277 v so the line current is 15,000 / 277 or 54 amps. The secondary has a line-to-neutral voltage of 120v so the current is 15,000/120 or 125 amps.
DNA is replicated.
This point is called critical point.
In an electromagnetic wave, the electric and magnetic fields are perpendicular to each other and are in phase.
Across a 480 volt three phase system, 480 volts should appear across L1 and L2, L2 and L3 and L3 and L1.
A voltage of 380 volts is a three phase voltage. On a three phase four wire system, each phase leg to neutral (grounded) will give you 220 volts. This voltage is obtained by dividing the phase voltage by 1.73, as the phase legs are generated 120 degrees from each other. Square root of three is 1.73 divided into 380 equals 220 volts.
You should have about 230 volts between any pair of 3-phase service legs: L1-L2, L2-L3, L3-L1. If the voltage measured between any one pair results in low or no voltage, then you have a fuse or circuit problem.
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
Using a properly rated voltmeter and following all safety precautions, check from phase to phase on each phase on the secondary side. phase 1-2 then 2-3 then 1-3 and they should all be within a few volts of each other.
For a single phase circuit, the equation you are looking for is I = W/E. Amps = Watts/Volts.
Sounds like both phase wires are connected to the same phase.
For the USA its 240V (120V on each line/phase).
208 is a three phase wye connection voltage. To obtain the each individual coil voltage the 208 is divided by 1.73 which equals to 120 volts. Hence you have 3 phase 208 voltage on the phase legs and 120 volts to the wye point which is grounded. This same formula is used on any 3 phase system. 600/347, 480/277, 208/120.
US homes use a 240 volt single phase 'Edison' system. It is a 3-wire (4 with the ground) system. Phase to phase measures 240v, while each phase to neutral measures 120v.
600 volts between any two wires. The phase has nothing to do with voltages, only current relationship.
A light bulb connected between to wires, each having 300 volts to ground that are in phase, will not light, because there is no differential voltage available to do any work. If each wire has 300 volts to ground and are out of phase (600 volts between them) the light bulb will be lit, if it is rated at least for 600 volts, otherwise it will burn out.