The Ampere is named after André-Marie Amprére, one of the main discoverers of electromagnetism. Note: The ampere was not "discovered" per se. It is a unit of measure for electric current, and electric current was know to exist well before it was qualified (defined) and quantified (measured).
UK Mains is 230V therefore 6 KW is 6000/230 = 26 Amps. 3 phase is slightly different....... 6000/400V = 15 Amps/root 3 = 8.67 Amps per phase.
An electric flow, is Current. Measured in Amps(Amperes)
Ampere is the unit used to measure the current.
Watts is the amount of power the heater has and amps would be the draw- if it is a 120 volt heater than the amps would be 12.5 amps and it is instantaneous
A 16 mm squared wire is equal to a #5 on the AWG scale. The electrical code book does not have amperage capacities for odd numbered wires. In North America the #6 copper conductor with an insulation factor of 75 or 90 degrees C is rated at 65 and 75 amps respectively. A #4 copper conductor with an insulation factor of 75 or 90 degrees C is rated at 85 and 95 amps respectively.
Multiply the vots by the amps to find the volt-amps. Or divide the volt-amps by the voltage to find the amps.
One 150 watt inverter reports 0.2 Amps (=approx 2.4watts) Another inverter (180 watts?) reported 0.4 Amps If you find a fairly complete spec sheet, it may tell you the Amps or Watts that it uses under "No Load". I'm the originator of the question, and I discovered the "additional" specs.
0.35897 amps = 0.35897 amps.
200ma is .200 amps or .2 amps
7 amps
Yes, the current measured in amps is the same as the keyword "amps."
Amps is amps be it DC or AC.
.1 amps will give you .1 amps.
There are 20 million amps or 20,000,000 amps.
In 50 VA the V stands for volts and the A is for amps. Hence the formula you are looking for is 50/240 = Amps.
What is the generator amps
To convert high voltage (HV) amps to low voltage (LV) amps, you can use the formula: HV amps = LV amps x (LV voltage / HV voltage). By rearranging the formula, you can calculate LV amps by dividing HV amps by the ratio of HV voltage to LV voltage.