you are freering to the internal clock speed and the external clock speed corect? ECLK or ECLKNOT are external clocks to the microprocessor. they do not run it. they are for the microprocessors supporting hardware. the internal frequency is what the processor actually uses. the ECLK is divided by two( a 6MHZ cycle take half as long a 3MHZ, right). the reason external (E) clocks run twice as fas as a processor is because there is not much data that can be processed in one cycle. it also allows the supporting architecture to access the data twice as it is processed. think about accessing a memory slot, it would use one ECLK cycle to locate the slot and one ECLK cycle to right the data to the processor. reading memory is a very simple task, but it still take two cycles. if the ECLK didnt run at twice the speed of the internal clock, the processor would be idle half of the time. actually there is a frequency devider circuit using 555 timer which devides the crystal frequency by 2......and the microprocessor components function proper at 3.14 Mhz.
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∙ 14y ago108 to 108 MHz is the radio frequency range assigned to the audio portion of broadcast television channels.
None. A byte is a unit of storage (in this case), hertz is a unit of frequency.
The calculation for a frequecy to wavelength is:speed of light/frequency = wavelength.e.g. freq = 28 mHz approximate speed of light = 300^6 in metres per second.(cancelling the zeros)300/28 = 10.7 metres28 mHz = c.ten metre wavelength.For AM/FM radio, the usual frequencies are:Longwave AM Radio = 148.5 - 283.5 kHz (LF)Mediumwave AM Radio = 530 kHz - 1710 kHz (MF)Shortwave AM Radio = 3 MHz - 30 MHz (HF)Average FM Radio = 76 MHz
The derived SI unit for frequency is hertz (Hz) The common metric multipliers are: kilohertz (kHz) = 1,000 Hz Megahertz (MHz) = 1,000,000 Hz and Gigahertz (GHz) = 1,000,000,000 Hz.
MHz is the abbreviation for megahertz. 1 million Hertz = 1 megahertz. A hertz is a measurement of frequency = 1 cycle per second. 900 MHz = 900,000,000 cycles per second. This is not a figure which can be translated into distance. Your question is akin to asking what is 60 miles per hour in tons.
Since the 8085 has a maximum clock frequency of 6 MHz, increasing the crystal frequency from 5 MHz to 20 MHz, a corresponding clock frequency change of 2.5 MHz to 10 MHz, the chip would malfunction.
The clock speed of the 8085 depends on the particular chip chosen. The basic 8085 could run up to around 3 MHz. The -1 version could run up to around 6 MHz. The -2 version could run up to around 5 MHz. In each case, the crystal frequency had to be exactly twice the desired clock frequency, i.e. 6 Mhz, 12 MHz, and 10 MHz, respectively. In all cases, the minimum clock frequency was 500 KHz. (Crystal 1 MHz)
The operating frequency of 8085 is 3 mhz to 5 mhz
There is no 8085 that operates at 101 MHz. The fastest 8085 operates at 12 MHz, requiring a 24 MHz crystal.
The crystal frquency in an 8085 system is twice the desired clock frequency, so a crystal of 2.2 MHz is required to operate at 1.1 MHz.Note: Clock frequency is not the same as instructions per second, because the instructions in an 8085 take a variable number of clock cycles, between 4 and 18, to execute.
From the Wikipedia article, it looks like they would operate at 3, 5, or 6 megahertz (MHz), or maybe it's 3.5 MHz and 6 MHz (they use 3,5 - not sure if that's a European decimal point or a comma)
Because it is the top operating speed for that IC
Maximal clock speed. 8085: ? 8085A: 3 MHz 8085AH: 5 MHZ
MAximum clock frequency of 8086 is 5MHZ.
A clock with a period of 1 ns has a frequency of 1 GHz, or 1000 MHz.
Internally two crystal oscillator cycles are used as one single cycle. During one single crystal cycle it is made to logic high and logic low in next cycle so, that 50% duty cycle is maintained.
At a clock frequency of 5 MHz (10 MHz crystal) the 8085 has a clock period of 200 ns. An instruction using 18 cycles would use 3.6 us. (Microseconds)This is for the case with no wait states. Each wait state adds 200 ns. Since an 18 cycle instruction has 5 memory accesses, one wait state per access would add 1 us to the execution time.