answersLogoWhite

0

What else can I help you with?

Related Questions

What is the insertion of the brachioradialis muscle?

The brachioradialis muscle inserts onto the styloid process of the radius in the forearm.


What muscle is attached at the lateral supracondylar ridge?

The muscle attached to the lateral supracondylar ridge is the "Brachioradialis" with an insertion point in styloid process of the radius.


What muscle inserts on radius?

The biceps brachii muscle inserts on the radius bone. It originates from the scapula and crosses both the shoulder and elbow joints to insert on the radius, allowing it to flex the elbow and supinate the forearm.


What is the difference between brachialis and brachioradialis?

The brachialis muscle is located deep to the biceps brachii and is the main flexor of the elbow joint. The brachioradialis muscle is a superficial muscle located on the lateral side of the forearm that aids in both elbow flexion and forearm supination.


Where is the radius muscle in the body?

The radius is a bone in the forearm, not a muscle.


What is the muscle that attaches shoulder blade at one end and the radius bone at the other end?

There is no muscle that attaches at the shoulder blade and the radius. The radius is one of two bones in the forearm.


What muscle is connected to the radius bone?

There are several, the main one being the biceps brachii.


What is the radius of a cylinder?

The radius of a cylinder is half the thickness of its circular cross section.


Which bone does the biceps muscle pull?

radius


Is your radius a bone or muscle?

it is a bone present in lower fore arm, along your thumb....... not at all a muscle....


Describe the cross section of a basketball vertical hortizontal and angled?

They are all circles. The vertical and horizontal have the same radius as the ball while the angled cross section has a smaller radius.


What is the radius of a cross section of a sphere that is 3 units from the center of the sphere?

If the radius of the sphere is R units then the radius of the cross section is sqrt(R2 - 32) Therefore the cross sectional area is pi*(R2 - 32) square units.