E. coli binds with lactose which changes its conformation so that it no longer binds to DNA. This allows the lactose operon to be transcribed.
E. coli can metabolize glucose and grow well. It can also metabolize sucrose, but usually not as efficiently as glucose. However, E. coli typically cannot metabolize lactose unless it carries the necessary enzymes, such as beta-galactosidase from the lac operon. Without the ability to metabolize lactose, E. coli will not grow as well in a mixture of glucose, sucrose, and lactose compared to a mixture of only glucose and sucrose.
yes it is lactose positive
Lactose metabolizing enzymes need not be made when lactose is not present.This means when glucose is present, the cell does not waste energy/resources on creating these enzymes.
it is by lac operon syastem
The genes that produce the enzymes needed to break down lactose are not expressed.
the presence of lactose
no
The lac genes in E. coli are regulated by the lac operon, which is controlled by a repressor protein. The repressor binds to the operator region of the DNA, blocking the transcription of the lac genes. When lactose is present, it binds to the repressor, causing a conformational change that releases the repressor from the operator, allowing for the expression of the lac genes.
By controlling gene expression, E. coli bacteria conserve resources and produce only those proteins that are needed
Escherichia coli needs the enzyme β-galactosidase to break down lactose. This enzyme cleaves lactose into its constituent sugars, glucose and galactose, which can then be used by the bacteria as a source of energy.
The organism likely to be found in a urine culture that is a Gram-negative rod and a lactose fermenter is Escherichia coli. E. coli is a common cause of urinary tract infections and is characterized by these microbiological properties.