Light and radio signals seldom travel in straight lines through air, because the
pressure, temperature, and density of air change with altitude. Light and radio
signals almost always curve vertically, and usually downward.
If you were to draw a picture of the real earth's surface, with the real path of a
light beam or radio signal traveling above it, the surface of the earth would curve
downward on the drawing, and the light or radio signal would also curve above it.
The distance between the surface and the light or radio signal would change across
the drawing, depending on how strongly the signal curved, and in which direction
(up or down).
It would be possible to distort the drawing in such a way as to make the light
or radio signal appear to be a straight line. In order to do that, you'd have to
change the curvature of the earth's surface on the drawing, and maintain the
original spacing between the surface and the radio signal at every point.
The number by which you have to multiply the true earth radius in order to
make the light or radio signal's path appear straight on the drawing, is the
"effective earth radius factor". It's a characteristic of atmospheric conditions
(specifically, the vertical gradient of the atmosphere's index of refraction),
and it's used in designing the optimum physical configuration of point-to-point
radio links, i.e. how high above the ground to mount the antennas at each end
of the link.
If a planet has twice the mass of Earth, its radius would need to be larger than Earth's to maintain the same gravitational field strength at its surface. Specifically, to achieve equivalent gravitational acceleration, the radius must increase by a factor of about 1.414 (the square root of 2), not 2. This is because gravitational field strength is directly proportional to mass and inversely proportional to the square of the radius (g = G * M / r²). Therefore, a radius larger by a factor of 2 would actually result in a lower gravitational field strength than that of Earth.
Venus has a radius of about 6,052 kilometers, which is about 95% of Earth's radius.
Since the distance from the Earth's center is doubled, the force will be reduced by a factor of 4.
To determine the radius of the larger cylinder, we need to know the radius of the smaller cylinder and the scale factor between the two cylinders. If the scale factor is provided, multiply the radius of the smaller cylinder by this factor to find the radius of the larger cylinder. Without specific measurements or a scale factor, we cannot calculate the radius of the larger cylinder.
Venus' radius = 0.95 of Earth's Venus' mass = 0.815 of Earth's
radius is 2
For a planet to have the same gravitational field strength at its surface as Earth while having twice its mass, its radius must increase. The gravitational field strength ( g ) is given by the formula ( g = \frac{G \cdot M}{R^2} ), where ( G ) is the gravitational constant, ( M ) is mass, and ( R ) is radius. If the mass ( M ) is doubled, to maintain the same gravitational field strength ( g ), the radius ( R ) must be increased by a factor of ( \sqrt{2} ), not 2. Therefore, the radius would need to be larger by a factor of approximately 1.414.
If the radius is tripled then the Area will be greater by a factor of 9. And the circumference will be greater by a factor of 3.
The Earth's radius is approximately 6,371 kilometers and 3,959 miles.
The weight of a body when raised above the Earth to a height equal to its radius will be 1/4 of its weight at the surface of the Earth. This is because the force of gravity decreases with distance from the center of the Earth, following an inverse-square law.
If you are a believer, then God did but if you are not, then nobody did. The radius of the earth existed and therefore ots radius did before there was any form of life on earth to invent it.
If the radius of the Earth were doubled, you would experience approximately one-fourth (1/4) of the original gravity. This is because gravity is inversely proportional to the square of the distance between two objects, so doubling the radius would reduce the gravitational force by a factor of 4.