The molar mass of glucose is 180.15588 g/mol.
The molar mass of glucose is 180,16 g.
To find the mass of 2.56 moles of glucose (C₆H₁₂O₆), first determine the molar mass of glucose. The molar mass is approximately 180.18 g/mol. Therefore, the mass of 2.56 moles of glucose can be calculated as follows: 2.56 moles × 180.18 g/mol = approximately 461.66 grams.
The answer this question you first have to find the molar mass of glucose: Carbon 12.01 g (atomic mass of element) * 6 (amount of atoms in glucose) Hydrogen 1.008 g * 12 Oxygen 16.00 g *6 Add the values together to get the molar mass. 180.56 g 180.56 is the molar mass of glucose in 1 mol. You can set up a proportion to solve this particular problem. 180.56 g ? g ------------ = ------------- 1 mol 0.500 mol The answer would be 90.078 g.
Yes, glucose and fructose have the same molar mass, which is approximately 180.18 g/mol. Both are monosaccharides with the molecular formula C6H12O6, differing only in their structural arrangement. This structural difference is why they are classified as isomers, but their molar mass remains identical.
To make a 1 molar solution of glucose in 0.5 L of water, you would need to dissolve 90.1 grams of glucose powder. This is because the molar mass of glucose (C6H12O6) is approximately 180.2 g/mol, and for a 1 molar solution in 0.5 L of water, you would need 1 mole of glucose, which is 180.2 grams.
Given that the unit 'mole' requires you to know the molar mass of what it is you're talking about, this question cannot be answered without that crucial information. e.g. The molar mass of glucose is 180.16g mol^-1 So, one mole of glucose would be 180.16g. This number would be different for any substance with a different molar mass. You need the molar mass of whatever you're talking about before you can make and such conversion.
The equation to find molar concentration is C= n/v (concentration= moles/volume). For 80g of glucose, you would first need to find the number of moles; n= m x mm (moles= mass x molar mass). Then you can input that number into the equation C= n/v.
The molar mass of glucose is approximately 180.16 g/mol. Therefore, one mole of glucose weighs approximately 180.16 grams.
To make a 1 molar solution of glucose (C6H12O6) in 1 liter of water, you would need to dissolve 180 grams of glucose. This is because the molar mass of glucose is 180 g/mol, so 1 mole of glucose weighs 180 grams.
To calculate the mass of 1.31 x 10^22 molecules of glucose, you first need to know the molar mass of glucose, which is approximately 180.16 g/mol. Then you can use this molar mass to find the mass of 1.31 x 10^22 molecules by multiplying the molar mass by the number of molecules given.
To find the molality of a solution, you need the mass of the solvent (usually water) in kilograms and the number of moles of solute (glucose). Given that the solution is 7.80% glucose by weight, you can calculate the mass of glucose in the solution and then convert it to moles using the molar mass of glucose. From there, you can find the molality by dividing the moles of glucose by the mass of the solvent in kilograms.
First find the molar mass... C -- 6 x 12 = 72 O -- 6 x 16 = 96 H -- 12 x 1 = 12, now add all -- 72 + 96 + 12 = 180 g/mole multiply 0.699 x 180 = 125.82 g --- Round to 126 g