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1 mole of HCl reacts with 1 mole of KOH. Therefore, 0.5 moles of KOH (500 mL = 0.5 L) are needed to neutralize 0.5 moles of HCl.
For 1 Liter you should take 88.8 mL concentrated HCL (be carefull) and add it to 900 mL water, and finally - after mixing- fill this up to 1000 mL with distilled water. (REMEMBER: ALWAYS ADD ACID TO WATER! -1N in 250 ml : add 22.2 mL to about (or less than) 225 mL water and dilute to final volume = 0.25L
CaCO3(s) + 2 HCl(aq) --> CaCl2(aq) + CO2(g) + H2O(l) 500 L * (1.40 mol HCl/1 L HCl) * (1 mol CaCO3/2 mol HCl) * (100.09 g CaCO3/1 mol CaCO3) = 35031.5 g CaCO3 35031.5 g * (1 kg/1000 g) = 35.0315 kg Therefore, about 35.03 kilograms of calcium carbonate is needed to neutralize 500 liters of 1.40 M hydrochloric acid.
Amount of HCl is 500cm^3 of .8M HCl = .8 x 500/1000 = 0.4 mol. Volume of 10M acid to give 0.4 mol = .4/10 = 0.04dm^3 = 40cm^3 Add 500 - 40 = 460 cm^3 of water. Caution : 10M HCl is highly corrosive and should be handled with care.
31 g of HCl divided by the molar mass of HCl to find how many mols. HCl --> H(1) + Cl(1) = molar mass of HCl 1.008(1) + 35.45(1)= 36.428 molar mass 31/36.428= 2.97 which is the mols of solute The mols of solute divided by kg of solute = molality 2.97/.500= 1.7 molality
8.3 grams HCl (1 mole HCl/36.458 grams) = 0.23 moles HCl ------------------------
1M HCl means there is 1 mole of HCl in 1 liter of solution. To convert to 1N HCl, you need to consider the equivalent weight of HCl, which is its molecular weight as it is a monoprotic acid. So, in this case, 1M HCl is equivalent to 1N HCl.
The chemical formula (not symbol) of hydrogen chloride is HCl; for a diluted solution you can use "HCl dil." but this isn't a standard formula.
1 m HCl is not more reactive than 4m HCl, but 4m HCl is more concentrated.
They all produce water, and a type of salts. NaOH + HCL ---> H2O + NaCl KOH + HCl ---> H2O + KCl
In the experiment, excess HCl was added to the solution containing KHCO3. This ensured that all of the KHCO3 would react completely, as any unreacted KHCO3 would still be neutralized by the excess HCl.
In a solution of HCl, all of the HCl molecules ionize completely in water to form H+ and Cl- ions. Therefore, the concentration of OH- ions in a HCl solution is negligible since there are no OH- ions produced in the dissociation of HCl.