A projectile fired directly upwards has no positive velocity. Its only velocity is attributed to the force of gravity, which is -9.8 meters per second squared.
The speed of the body at the highest point is 0 m/s. The acceleration acting on the body is the acceleration due to gravity (-9.81 m/s^2), which acts downward throughout the motion.
The magnitude of the upward acceleration of the load of bricks is the measure of how fast the load is moving upwards.
The acceleration of the ball just before it hits the ground is equal to the acceleration due to gravity, which is approximately 9.81 m/s^2 downward.
The total time of flight for a ball thrown vertically upwards and returning to its starting point is twice the time taken to reach maximum height. Therefore, the time taken to reach maximum height is 4 seconds. Given that the acceleration due to gravity is -9.8 m/s^2, using the kinematic equation v = u + at, where v is the final velocity (0 m/s at maximum height), u is the initial velocity, a is the acceleration due to gravity, and t is the time, you can solve for the initial velocity. Substituting the values, u = 9.8 * 4 = 39.2 m/s. Therefore, the initial velocity of the ball thrown vertically upward is 39.2 m/s.
When a cricket ball is projected vertically upward, the acceleration acting on the ball is gravitational acceleration directed downward. This causes the ball to slow down until it reaches the highest point of its trajectory, then it accelerates back downward due to gravity.
When an object is thrown upward, work is done against gravity as the object moves upward. The amount of work done is equal to the force applied to lift the object multiplied by the distance it moves vertically.
No, the acceleration at the highest point is never 0.
The direction of acceleration would be vertically upward, since the net force is acting in that direction. The horizontal motion of the balloon being blown westward does not affect the acceleration in the vertical direction.
At the highest point, the velocity of an object thrown vertically into the air is momentarily zero as it changes direction. This is the point where it transitions from going upward to downward.
The ball is affected by the force of the earth's gravity.
The acceleration of a ball at the top of its trajectory when thrown straight upward is equal to the acceleration due to gravity, which is approximately 9.81 m/s^2 downward. At the top of its trajectory, the ball momentarily comes to a stop before reversing direction and accelerating downward.
Yes, when a ball reaches the top of its trajectory when thrown vertically upward, it is momentarily at rest before gravity pulls it back down. This is a state of dynamic equilibrium because the forces acting on the ball are balanced at that point.