The acceleration of the ball just before it hits the ground is equal to the acceleration due to gravity, which is approximately 9.81 m/s^2 downward.
The speed of the body at the highest point is 0 m/s. The acceleration acting on the body is the acceleration due to gravity (-9.81 m/s^2), which acts downward throughout the motion.
The force acting on a body thrown vertically upwards is gravity. Gravity pulls the body back towards the ground, causing it to slow down and eventually stop at its highest point before falling back down.
From the time the object leaves your hand, its acceleration doesn't change at all ... it remains constant at 9.8 meters (32.2 feet) per second2 downward. Well, we have to admit that the acceleration does change to zero once the object hits the ground.
The downward acceleration of a thrown object in projectile motion is constant and equal to the acceleration due to gravity, which is approximately 9.81 m/s^2 on Earth. This acceleration acts vertically downward and affects the vertical motion of the object while the horizontal motion remains unaffected.
The speed of a ball thrown upward upon striking the ground will be the same as the speed at which it was thrown, but in the opposite direction. The speed of a ball thrown downward upon striking the ground will be faster than the speed at which it was thrown due to the acceleration from gravity.
The speed of the body at the highest point is 0 m/s. The acceleration acting on the body is the acceleration due to gravity (-9.81 m/s^2), which acts downward throughout the motion.
An object thrown vertically up wards from the ground returned back to the ground in 6s after it was thown up if it reached a height of 12m calculate?
The force acting on a body thrown vertically upwards is gravity. Gravity pulls the body back towards the ground, causing it to slow down and eventually stop at its highest point before falling back down.
The answer depends on whether the ball is thrown vertically upwards or downwards. That critical piece of information is not provided!
Acceleration is dependent on the initial velocity of how fast the object is leaving the projectile. The vertical acceleration is greater when the object is falling than when the object reaches the peak in height. However, if the object is thrown horizontally and there is no parabola in its shape then there is not as great of an acceleration.
From the time the object leaves your hand, its acceleration doesn't change at all ... it remains constant at 9.8 meters (32.2 feet) per second2 downward. Well, we have to admit that the acceleration does change to zero once the object hits the ground.
The downward acceleration of a thrown object in projectile motion is constant and equal to the acceleration due to gravity, which is approximately 9.81 m/s^2 on Earth. This acceleration acts vertically downward and affects the vertical motion of the object while the horizontal motion remains unaffected.
The speed of a ball thrown upward upon striking the ground will be the same as the speed at which it was thrown, but in the opposite direction. The speed of a ball thrown downward upon striking the ground will be faster than the speed at which it was thrown due to the acceleration from gravity.
if the bal is thrown by making 45 degree angles. with the ground..it will travel maximum distance...
False, provided the drop occurs no sooner than the throw, and the ground is flat .
The ball thrown straight down from a bridge will experience an acceleration due to gravity. On Earth, this acceleration is approximately 9.81 m/s^2 and acts in the downward direction. The acceleration will cause the ball to increase in speed as it falls towards the ground.
The acceleration of an object thrown vertically upwards can be calculated using the kinematic equation (v_f^2 = v_i^2 + 2a \cdot d), where (v_f) is the final velocity, (v_i) is the initial velocity, (a) is the acceleration, and (d) is the distance. Given that the object is thrown vertically upwards, the equation becomes (0 = (44 , \text{m/s})^2 + 2 \cdot a \cdot (-3.5 , \text{m})). Solving for (a), we find that the acceleration is approximately -104 m/s², which indicates that the object is accelerating downwards.