If a homozygous black guinea pig (BB) is crossed with a homozygous white guinea pig (bb), all offspring will inherit one black allele (B) from the black parent and one white allele (b) from the white parent, resulting in heterozygous offspring (Bb). Since black fur is dominant over white fur, all offspring will have black fur. Therefore, the probability of an offspring having black fur is 100%.
75%
75%
depends if the black fur gene is dominant.. if it is... then yu would cross BB with bb making all heterozygous genotypes(Bb) therefore, having all possible offspring with black fur so theres a 100% probability of offspring with black fur(:
There different genotypes and two different colors Black fur is dominant --> F White fur is recessive --> f The parents are bot Ff (heterozygotes, and because black fur is dominant they have a black fur). If they mate, you get parents: Ff x Ff Offspring: FF Ff Ff ff so 25% will be homozygous for Black fur 2x25=50% will be heterozygous, and have a Black fur and 25% wil be homozygous for White fur. Hence, of their offspring, 75% will have a black fur and 25% will have a white fur
The answer depends on how big the litter is: as the litter size increases the probability of one black fur increases. But as it gets larger still, the probability falls because two or more black furs become more probable.
Darkening of the fur.
for what animal. it all depends on the dominant gene (allele) and recessive. the genotype of the parents needs to be set up in a Punnett square and with that data you can determine the probability that an animal will have brown fur
100% because BB is dominant over bb and all the crosses make Bb
no thats fine its just its fur growing. do not worry!
To have offspring with black fur, both parent dogs must carry the gene for black fur. This gene is usually dominant, meaning that if at least one parent carries it, there's a high chance the offspring will have black fur. If both parents have black fur, then their offspring will also have black fur.
American red squirrel