If a homozygous black guinea pig (BB) is crossed with a homozygous white guinea pig (bb), all offspring will inherit one black allele (B) from the black parent and one white allele (b) from the white parent, resulting in heterozygous offspring (Bb). Since black fur is dominant over white fur, all offspring will have black fur. Therefore, the probability of an offspring having black fur is 100%.
75%
75%
depends if the black fur gene is dominant.. if it is... then yu would cross BB with bb making all heterozygous genotypes(Bb) therefore, having all possible offspring with black fur so theres a 100% probability of offspring with black fur(:
There different genotypes and two different colors Black fur is dominant --> F White fur is recessive --> f The parents are bot Ff (heterozygotes, and because black fur is dominant they have a black fur). If they mate, you get parents: Ff x Ff Offspring: FF Ff Ff ff so 25% will be homozygous for Black fur 2x25=50% will be heterozygous, and have a Black fur and 25% wil be homozygous for White fur. Hence, of their offspring, 75% will have a black fur and 25% will have a white fur
The answer depends on how big the litter is: as the litter size increases the probability of one black fur increases. But as it gets larger still, the probability falls because two or more black furs become more probable.
If two heterozygous rats (Bb) are mated, where B represents the dominant black fur and b represents the recessive white fur, their offspring would follow a typical Mendelian inheritance pattern. The expected genotypic ratio of the offspring would be 1 BB (homozygous black) : 2 Bb (heterozygous black) : 1 bb (homozygous white). Consequently, about 75% of the offspring would have black fur and 25% would have white fur.
Darkening of the fur.
To calculate the probability of a homozygous dominant (BB) offspring from a cross between two rabbits, we need to consider their genotypes. If both parents are heterozygous (Bb), the possible offspring genotypes would be BB, Bb, Bb, and bb, giving a probability of 1 out of 4, or 25%, for a homozygous dominant (BB) offspring. If one parent is homozygous dominant (BB) and the other is heterozygous (Bb), the probability of BB offspring is 1 out of 2, or 50%.
for what animal. it all depends on the dominant gene (allele) and recessive. the genotype of the parents needs to be set up in a Punnett square and with that data you can determine the probability that an animal will have brown fur
100% because BB is dominant over bb and all the crosses make Bb
The appearance of the offspring of a black mouse and a white mouse depends on the genetics of the parents. If the black mouse is homozygous for black fur and the white mouse is homozygous for white fur, all offspring would likely be black. However, if the black mouse is heterozygous, the offspring could be a mix of black and white, or even gray if there is incomplete dominance. Ultimately, the specific traits will depend on the alleles inherited from each parent.