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The belt-and-braces technique is easy enough:

>

> prefix_to_infix(stream, stack)

> if stack is not empty

> pop a node off the stack

> if this node represents an operator

> write an opening parenthesis to stream

> prefix_to_infix(stream, stack)

> write operator to stream

> prefix_to_infix(stream, stack)

> write a closing parenthesis to stream

> else

> write value to stream

> endif

> endif

> endfunc

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Program to convert a infix expression in to postfix and prefix expression in php?

To convert an infix expression to postfix and prefix in PHP, you can implement the Shunting Yard algorithm for postfix conversion and a modified approach for prefix conversion. For postfix, you use a stack to reorder operators based on their precedence and associativity while scanning the infix expression. For prefix, you can reverse the infix expression, convert it to postfix, and then reverse the resulting postfix expression. Here’s a brief code outline for both conversions: function infixToPostfix($infix) { // Implement the Shunting Yard algorithm to convert infix to postfix } function infixToPrefix($infix) { // Reverse the infix expression // Convert to postfix using infixToPostfix // Reverse the postfix result to get prefix } You would need to handle operators, parentheses, and precedence rules within these functions.


What is the time complexity of infix to post fix conversion algorithm?

O(nlogn)


Write an algorithm in c to convert an infix expression to a postfix expressionexecute your algorithm with the following infix expression as your input. m nk pgh a bc?

An algorithm can not be written with the following infix expression without knowing what the expression is. Once this information is included a person will be able to know how to write the algorithm.


What are the three kinds of affixes?

Prefix, suffix and infix


Algorithm for infix to prefix conversion?

Algorithm to Convert Infix to Prefix FormSuppose A is an arithmetic expression written in infix form. The algorithm finds equivalent prefix expression B.Step 1. Push ")" onto STACK, and add "(" to end of the AStep 2. Scan A from right to left and repeat step 3 to 6 for each element of A until the STACK is emptyStep 3. If an operand is encountered add it to BStep 4. If a right parenthesis is encountered push it onto STACKStep 5. If an operator is encountered then:a. Repeatedly pop from STACK and add to B each operator (on the top of STACK) which has same or higher precedence than the operator.b. Add operator to STACKStep 6. If left parenthesis is encontered thena. Repeatedly pop from the STACK and add to B (each operator on top of stack until a left parenthesis is encounterd)b. Remove the left parenthesisStep 7. Exit


Program to convert infix to prefix?

I dont have the idea about the program but I know that prefix means the first starting letters of a particular things. I really think so there is a progam to convert infix to prefix but i might have misunderstood your question can you make it little simpler please.


Convert infix to prefix to postfix?

(a + b) * c / ((x - y) * z)


Prefix suffix and infix examples with meaning and word definition?

An example of a prefix in the English language is pre, meaning before. An example of a suffix would be ing, meaning a verbal action. An example of an infix would be ful, meaning full of.


Which data structure convert logical to physical address?

Linear data structure is used to convert the logical address to physical address .Stack is used in this and the various conversion such as postfix,prefix and infix notation are come in this


What is prefix expression?

Example: prefix: * 2 + 3 4 infix: 2 * (3+4) postfix: 2 3 4 + *


Who invented postfix and infix?

infix: old Egyptians/Assirs some thousands year before prefix: Jan Łukasiewicz (Polish Notation) postfix: Burks, Warren, and Wright (Reverse Polish Notation)


Prefix to postfix conversion using C programming?

#include<stdio.h> #include<conio.h> #include<string.h> char symbol,s[10]; int F(symbol) { switch(symbol) { case '+': case '-':return 2; case '*': case '/':return 4; case '^': case '$':return 5; case '(':return 0; case '#':return -1; default :return 8; } } int G(symbol) { switch(symbol) { case '+': case '-':return 1; case '*': case '/':return 3; case '^': case '$':return 6; case '(':return 9; case ')':return 0; default: return 7; } } void infix_to_postfix(char infix[],char postfix[]) { int top=-1,j=0,i,symbol; s[++top]='#'; for(i=0;i<strlen(infix);i++) { symbol=infix[i]; while(F(s[top])>G(symbol)) { postfix[j]=s[top--]; j++; } if(F(s[top])!=G(symbol)) s[++top]=symbol; else top--; } while(s[top]!='#') { postfix[j++]=s[top--]; } postfix[j]='\0'; } void main() { char infix[30],postfix[30]; clrscr(); printf("Enter the valid infix expression\n"); scanf("%s",infix); infix_to_postfix(infix, postfix); printf("postfix expression is \n %s", postfix); getch(); }