The number of bits needed to represent one symbol depends on the total number of unique symbols. The formula to calculate the number of bits required is ( n = \lceil \log_2(S) \rceil ), where ( S ) is the number of unique symbols. For example, to represent 256 unique symbols, 8 bits are needed, since ( \log_2(256) = 8 ).
5
A standard deck of playing cards has 52 cards. To determine how many bits are needed to represent each card, we can use the formula ( \lceil \log_2(52) \rceil ). Since ( \log_2(52) ) is approximately 5.7, we round up to 6 bits. Therefore, 6 bits are needed to uniquely represent each card in a standard deck.
A bit pattern can represent (2^n) symbols, where (n) is the number of bits in the pattern. For example, a 3-bit pattern can represent (2^3 = 8) different symbols, ranging from 000 to 111 in binary. Each additional bit doubles the number of possible symbols that can be represented.
To represent 64 characters, you would need 6 bits. This is because 2^6 equals 64, meaning six bits can encode 64 different values, sufficient for each character. Each bit can represent two states (0 or 1), and with six bits, you can create combinations to represent all 64 characters.
To represent an eight-digit decimal number in Binary-Coded Decimal (BCD), each decimal digit is encoded using 4 bits. Since there are 8 digits in the number, the total number of bits required is 8 digits × 4 bits/digit = 32 bits. Therefore, 32 bits are needed to represent an eight-digit decimal number in BCD.
18 in binary is 10010 Since 18 can't be written in term of 2 to the power x, the number of bits needed is 5. The answer is 5
8 bits if unsigned, 9 bits if signed
how many bits are needed to represent decimal values ranging from 0 to 12,500?
5
1200
A standard deck of playing cards has 52 cards. To determine how many bits are needed to represent each card, we can use the formula ( \lceil \log_2(52) \rceil ). Since ( \log_2(52) ) is approximately 5.7, we round up to 6 bits. Therefore, 6 bits are needed to uniquely represent each card in a standard deck.
45 in binary is 101101, so you need at least 6 bits to represent 45 characters.
To determine the minimum number of bits needed to store 100 letters and symbols, we first need to consider the total number of unique characters. Assuming we use the standard ASCII set, which includes 128 characters (letters, digits, and symbols), we can represent each character with 7 bits. Therefore, to store 100 characters, we would need a minimum of 700 bits (100 characters × 7 bits per character). However, if a larger character set like UTF-8 is used, it may require more bits for some characters.
A bit pattern can represent (2^n) symbols, where (n) is the number of bits in the pattern. For example, a 3-bit pattern can represent (2^3 = 8) different symbols, ranging from 000 to 111 in binary. Each additional bit doubles the number of possible symbols that can be represented.
To represent 64 characters, you would need 6 bits. This is because 2^6 equals 64, meaning six bits can encode 64 different values, sufficient for each character. Each bit can represent two states (0 or 1), and with six bits, you can create combinations to represent all 64 characters.
To represent an eight-digit decimal number in Binary-Coded Decimal (BCD), each decimal digit is encoded using 4 bits. Since there are 8 digits in the number, the total number of bits required is 8 digits × 4 bits/digit = 32 bits. Therefore, 32 bits are needed to represent an eight-digit decimal number in BCD.
24 bits are needed for the program counter. Assuming the instructions are 32 bits, then 32 bits are needed for the instruction register.