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When did V1 and V2 rocket bombs attacks start?
June of 1944
How many bombs were dropped in the blitz?
There were different varieties of bombs that fell on London, These were: * H.E. (High Explosive) bombs * Incendiary Bombs, also called Fire Bombs as they started fires. * Oil Bombs 1 in every 10 bombs that fell was a 'dud', which meant it did not blow up on impact. Some bombs had a delayed fuse, which meant they could explode at any time, before or after they had hit the ground. This meant that it was almost impossible to tell the difference between the bombs that were dropped. Civillians were evacuated from the area until the bombs had been deactivated. Bombs are still being found today. In 1944, two new weapons began to be used. They were the V1 and V2 bombs. A V1 bomb, offten called a doodlebug, had no pilot and made a droning sound when it flew. When the noise stopped people knew they had 15 seconds to get out before the explosion happened. As they had no pilot, may V1's fell into the sea or missed their targets and fell into the countryside. Almost 9,500 v1s were sent off towards london, but less than 2,500 actually got there. many were destrooyed by aircraft, guns and barrage baloons, and the rest just missed their targets. The first doodlebug to ever explode was in Swanscome in Kent. A V2 bomb was a much larger version of a V1 bomb. they flew without any noise, which meant no warning of where or when they were going to fall. They also flew too high to be shot down by aircraft or ground guns. The explosion was much larger with these bombs, but not so many were fired.
What were the names of the rockets that flew over and blew up in England?
There was the V1 rocket and then later the stronger V2 rocket
What were rockets used for in World War 2?
The German Army used them to power their V1 & V2 flying bombs (nicknamed buzzbombs) directed at London. Many were destroyed over open countryside by Royal Air Force pilots.
Did they use missiles in world war 2?
There is an example of the Germans using the first air launched guided missile in WW2. The Katushia rocket and the Nebelwerfewr were missile systems of sorts. The V1 & V2 Rockets were missiles, the V2 went into sub-space in flight.
When did V1 and V2 rocket bombs attacks start?
June of 1944
Great Britain gets the V1-2 punch?
I don't know what you are asking, but the V1 and V2 were German rocket-bombs used in World War 2.CorrectionThe V1 was not a rocket.
In the acceleration equation what do v1 and v2 represent?
v1 = initial velocity v2 = final velocity
What is the equation for the percentage difference of 20 and 31?
( | V1 - V2 | / ((V1 + V2)/2) ) * 100
What is the v1 v2 and rotate speed on a dc3?
v1 is design speed and v2 rotation speed
Will changing the order of your displacements in the vector diagram affect magnitude and direction?
No. Result= V1 + V2 = V2 + V1.
What is the formula for percentage change?
[ ((v2 - v1) / |v1|) * 100 ]
What is the average velocity when a person traveling on a straight line moves with a uniform velocity v1 for x distance and v2 for next equal distance?
Let t1 and t2 be the times for the two stages. Then t1 = x/v1 and t2 = x/v2 Total distance = x + x = 2x Total time = t1 + t2 = x/v1 + x/v2 = x*(1/v1 + 1/v2) Average velocity = total distance / total time = 2x divided by x/(1/v1 + 1/v2) = 2(1/v1 + 1/v2) which is the Harmonic mean of v1 and v2.
Difference between of rip v1 and rip v2?
Rip V1 is Classful routing protocol Rip V2 is Classless routing Protocol
How do you prepare 5 picomole solution from 32nanomole solution?
5 * 10**-12 mol 32 * 10**-9 mol Concentration (M) * Volume (L) = mols C1*V1=C2*V2 (5*10**-12)*V1=(32*10**-9)*V2 (5*10**-12)*V1/(32*10**-9)=V2 (5*10**-3)*V1/32=V2 The volume of the 5 picomolar solution that you wish take = V1 The volume of the 32 nanomolar solution that you need to make V1 at 5pM concentration = V2 Take V2, and place into graduated cylinder and fill to V1.
What is the advantage of a system with more than one type of output?
The most common multi output systems are used for getting differential output. i.e., if V1 and V2 are the 2 outputs, then usually the difference, V2-V1 or V1-V2 is used.
If acceleration=0, than according to "d=v2*t-1/2a*t^2" changed to get v2 is "v2=d+1/2a*t^2/t", but with acceleration=0, would v2=d V2=end velocity, d=distance, a=acceleration, t=time?
The equations of motion that relate velocity, distance, time and acceleration for the specific case of "constant acceleration" can be written as follow, acceleration a = (v2 - v1)/t from which v2 = v1 + at The distance covered during t time d = vav x t, where vav refers to average velocity in the process from v1 to v2. For the case of constant acceleration vav = (v1 + v2)/2. Substituting in d we get d = (v1 + v2)/2 x t from which, v2 = 2d/t - v1 If we take the constant acceleration to be zero, a = 0, you can see that the second equation we wrote becomes, v2 = v1 (There is no acceleration), so our equation for the distance d becomes, d = v1 x t = v2 x t
