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How will you get 3 ohm resistance using 2 ohm resistance?
connect 2 2ohm resistors in parallel and connect it to a series 2ohm resistor
What is your observation of resistors in parallel resistors?
RParallel = 1 / Summationi=1toN (1 / Ri)
Two resistors are connected in parallel to a battery What must the votlage across these two resistors?
Both resistors will have the voltage of the battery.
The total resistance of a circuit with three 30 ohm resistors in parallel is ohms?
If the parallel resistors are equal, then the total resistance (in this case, with three resistors) will decrease by a factor of 3. I suggest you verify this with the standard formula for parallel resistance: 1/R = 1/R1 + 1/R2 + 1/R3, replacing the value 30 for R1, R2, and R3, and calculating R, the combined resistance.
What happens to resistance when resistors are wired in parallel delta circuit?
What do you mean by a 'parallel delta' circuit -is there such a connection.
How do you draw this you have three 20 ohm resistors available. how would you connect these three resistors to produce a 30 ohm equivalent you must use all three resistors?
You can achieve a 30 ohm equivalent resistance by connecting the resistors in a combination of series and parallel. Connect two resistors in series to get 40 ohms, then connect the third resistor in parallel with this combination to achieve a total resistance of 30 ohms.
Can two electric resistors connect in both series and parallel?
yes two resistors can connect both in series and parallel because when you connect two resistors in a closed loop, the same intensity of current flows across them and also they are connected to the same nodes which are the conditions for series and parallel connections respectively.
How do you connect several resistances if you want to decrease in total resistance without reducing the number of resistors?
The resistors should be connected in parallel .
How can i connect 50 RGB Led's parallel to a 12v 2A line?
50 resistors
What is the equation for power current and voltage?
1. Formula with respect to the current(I) & resistance(R)V = I.R2. Formula with respect to watt power(P) & current(I)V = P/I
If we connect two identical resistors in series to a non-ideal DC voltage source is 0.87 What is the efficiency of the source is . What is the efficiency of the source if we connect the two resistors to it in parallel?
urgently needed
How will you get 3 ohm resistance using 2 ohm resistance?
connect 2 2ohm resistors in parallel and connect it to a series 2ohm resistor
How can you connect resistors to produce an equivalent resistance which is the same as the resistance of each individual resistor?
You can connect 4 resistors in series-parallel, i.e. two in series, both in parallel with another two, and the effective resistance would be the same as one resistor. Similarly, you can connect nine resistors in 3x3 series-parallel, or 16 resistors in 4x4 series-parallel, etc. to get the same resistance of one resistor.
How will you join 3 resistors of 2 ohm each so that the effective resistance is 3 ohm?
You can achieve an effective resistance of 3 ohms by connecting the resistors in series. Connect two resistors in series to get a combination of 4 ohms. Then, connect this combination in parallel with the third resistor to achieve an overall resistance of 3 ohms.
Three equal resistors connected in series across a voltage source dissipate a power of 10W what sould be the power desipated if same resistors are connected in parallel?
If three equal resistors are connected in parallel, the equivalent resistance will be one-third of the resistance in series. This lower resistance will result in a higher current flowing through the resistors when connected in parallel compared to when they are in series. Therefore, the power dissipated by the resistors in parallel will be greater than 10W.
Twelve identical wires of resistance 6 ohm each are arranged to form the edges of cube the effective resistance bw the opp corners of cube is?
The effective resistance between opposite corners of a cube comprised of twelve 6 ohm resistors, one at each edge, is 5 ohms. There are several ways to solve this. One approach is to build a system of 12 equations in 12 unknowns, and solve them. Another approach is this... Consider that there are three resistors leaving the input node, and there are three resistors entering the output node. In between those three resistors, there are six resistors in a criss-cross matrix. (Draw it out, flattened, to see this.)Inspecting the six resistors in the center, you note that they are completely symmetrical. Since they are symmetrical, you can conclude that the voltage at the junction between the three input resistors and the six others is the same voltage. The same goes for the three output resistors. Said another way, the voltage across the three input resistors and the three output resistors is the same. Given two or more nodes in a circuit having the same voltage, you can draw a wire connecting them, i.e. a resistor of zero ohms. This does not change the characteristics of the circuit in any way, because zero voltage across any resistance is still zero amperes. Now that you have made these connections, look at the circuit. It has simplified to three parallel resistors, in series with six parallel resistors, in series with three parallel resistors. Three 6 ohm resistors in parallel is 2 ohms. Six 6 ohm resistors in parallel is 1 ohm. Three more 6 ohm resistors in parallel is 2 ohms. The total resistance is 2 + 1 + 2 ohms, or 5 ohms.
What is the equivalent resistance when resistors are in a cube?
The equivalent resistance, from corner to corner, of 12 resistors connected in a cube is 5/6 that of a single resistor.Proof:Start from one corner and flow current through to the opposite corner. You have three resistors. Each of those three resistors is connected to two resistors, in a crisscross pattern. Those six resistors are then connected to three resistors which are connected to the other corner. By symmetry, the voltages at the upper junctions are the same, and then same can be said for the lower junction. You can then simplify the circuit by shorting out the upper junctions and (separately) the lower junctions. This means the circuit is equivalent to three resistors in parallel, in series with six resistors in parallel, in series with three resistors in parallel. This is 1/3 R plus 1/6 R plus 1/3 R, or 5/6 R.
