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A trapeze artist swings in simple harmonic motion with a period of 3.8 s Calculate the length of the cables supporting the trapeze?
3.6m
AV cables definition?
"A/V cables" (or any variation thereon) means audio/video cables. These cables carry sound and picture within the home for almost all home-entertainment equipment, such as televisions, VCRs, and DVD players. They are even used directly or with a plug adapter by other devices such as video cameras or game machines. Until recently, the nomenclature referred only to the set of three A/V cables with one for picture (video), and two for stereo sound (audio). These cables are of the shielded type, terminated with a male connector, called a phono plug or RCA plug, on each end. The carried signals are all analog; the video signal carried is called composite video. Cable manufacturers color-code the cables or the connectors as follows: yellow for video, red for right-channel sound, and black for left-channel sound. But with the arrival of newer means of and standards for carrying sound and picture over wires, "A/V cables" can refer to any combination of wire types carrying sound and picture. Some other standards and technologies are S-video, component video, digital audio, digital optical audio, DVI video, and HDMI audio/video.
What are the uses of cables?
Different types of cables are used for different purposes:Power cables are used for the transmission of electrical power.Chain cables are used in vehicles like motorbikes.Optical fibers are used to send signals in the form of electric current over long distances.Cables are used in the movement of elevators.Cables such as ropes are used for hauling, most commonly used in ships.Such cables are designed to connect medical and laboratory instruments and equipment. They transmit power and/or data and usually have an abrasion-resistant jacket that provides relatively low surface friction and mechanical durability.You will find the best quality medical cable from peterstechnology.com.
Why is electricity is transported in high voltage but not in current?
This is done in order to minimize power losses in the power distribution network due to the resistance of the transmitting cables. It should be noted that for a given cable resistance, voltage drop, and thus power dissipated in the cable and not available to use, is directly related to the current flow through the conductor.According to the Power Law: P = I2 ×R, that is power (in this case, power lost) is equal to current squared times resistance. To deliver power, it takes amps and volts. If you raise the volts, you can reduce the amps and still get the same power. If you reduce the amps, you lower the losses. Did you notice the squared term in the formula? That means if you reduce the current to one-tenth of the original value, your losses go down to one one-hundredth of what they were.This is a huge issue for the utilities. Every kW lost is one they cannot collect money for, yet they still have to pay for fuel to generate it, they have to size the generator bigger to supply it, and they have to size the transmission system to carry it. There are other good reasons too (see below), but minimizing line loss is the $main$ one. A few transmission systems have been designed at 1.2 million volts. The utilities would have billion-volt systems if they could figure out how to do it.2nd AnswerA major reason is that, to carry the same amount of power, if the transmission voltage is made higher, then, even though a thinner cable has a higher resistance for a given length, the cables can be made thinner and lighter in weight.Use of a higher transmission voltage saves a tremendous amount of money in many ways. For example for the expensive material used for the cables (often a steel multi-strand core wound with an outer skin of copper, aluminum, or similar good conducting wires) and for the weight and costs of construction and erection of the towers that carry the cables across the countryside.To carry 400 kV (= 400 kilovolts = 400 thousand Volts) the steel towers have to be taller and the porcelain insulators have to be longer than they would have to be for cables carrying lower voltages but the cost of making the towers taller and the insulators longer is far less than the cost of the extra weight of the much thicker cables that would be needed to carry the same power at a lower voltage. *** (See Note below for more explanation)There are many other costs which have to be reckoned when deciding what voltage to use for long-distance power distribution. For example the high cost of the massive power Transformers and big switching stations that have to be included in the power distribution network; the power that is lost from the cables - radiated to the surrounding air as heat - because of the electrical resistance of the materials from which the cables are made.The above answer just gives a very simplified overview of the kinds of things a skilled power transmission engineer has to work with and calculate when designing a new power transmission network.3rd AnswerTransmission and quantum of electricity can be considered analogous to hydraulics. Reckon voltage as pressure, the longer the distances, the higher the pressure required to pump. That is why for long distance transmission high pressure (voltage here) is required, failing which, the power will not reach the destined end. It will dissipate on the way. Reckon current as quantity which will be drawn from the pipeline (cables here) at the pressure/voltage required.*** Note:If we use the Electric Power Equation we can get an idea of what the descriptions given in the answers above really mean:P = V × I or, in words:P (power) = potential difference V (voltage) times current I (amperage)So, using simple mathematics we can say that:I = P / V or, in words:Current I (amperage) = P (power) divided by potential difference V (voltage)Now, as an example, if a small town needs to have a supply of power W of say 1 MW (= 1 megawatt = 1 million watts) to be delivered over cables from a power generation station:Calculation A:If the voltage V used for transmission through the cables is 1000 Volts then the current I in the cables would have to be:P / V = 1,000,000 / 1,000 = 1,000 ampswhich would require a very thick and heavy, and therefore very expensive, cable and associated support towers.Calculation B:If the voltage V used for transmission through the cables is 400 kV (= 400 kilovolts = 400,000 volts) then the current I in the cables would have to be:P / V = 1,000,000 / 400,000 = 2.5 ampswhich can be carried safely in a very much thinner, lighter and less expensive cable and support tower.Line supports are mainly two types:1. polesPoles are classified as wood poles, concrete poles and steel/aluminum poles.2. towersTowers are classified as self supporting towers and stayed/guyed towers.Self supporting towers are in two types: wide base and narrow base.Stayed towers are classified as portal type and V-type.
What cables are resistant to EMI?
Fiber optic cables transfer data signals in the form of light and it is faster than traditional electric cables. It is very helpful in good and speedy communication, network and broadcasting services. Visit americancableassemblies. com or call 413-283-2515 now. americancableassemblies. com/fiber-optic-cables/optitap/
What is the current capacity of two cables in parallel?
It will just be the sum of the current-carrying capacity of each individual cable.
Are transmission power cables capacity designed by voltage or by power is there any limit to the voltage that can pass?
Transmission power cables are designed by current carrying capacity.
Which table in BS 767112008 applies to the current carrying capacity of flat twin and earth cable?
The tables within Appendix 4; "Current-carrying capacity and voltage drop for cables and flexible cords." 4D1 to 4J4. For each type of cable, you will find (with a couple of exceptions) a Table A for current-carrying capacity values and following it, a Table B for voltage drop values.
How do you calculate derating factor for cables?
The derating factor for cables is calculated by considering various environmental factors such as ambient temperature, grouping of cables, and installation conditions. First, determine the cable's current-carrying capacity based on its specifications. Then, apply correction factors from relevant standards or tables for each influencing factor, multiplying these factors together to obtain the overall derating factor. Finally, multiply the original capacity by the derating factor to find the adjusted capacity for safe operation.
What do you understand by square mm of electric cables?
In European countries and elsewhere, the cross-sectional area of electric cables and busbars are expressed in square millimetres. The larger the cross-sectional area, the greater the current-carrying capacity.
What is the current carrying capacity of 18 gauge wire used in vehicle wiring?
Upto about 16 Amps, provided the cables aren't wrapped or bunched up somewhere hot.
What information can I find in the Romex ampacity chart?
The Romex ampacity chart provides information on the maximum current-carrying capacity of different types and sizes of Romex electrical cables. This helps determine the safe amount of electrical current that can flow through the cables without overheating or causing damage.
How can you calculate the current carrying capacity of 1 sq mm wire?
4amps can pass in 1sqmm of wire max it is universal. In the UK 1 sq. mm wire can take 10 amps max according to tables. Cables that become warm in use should be replaced by a thicker gauge.
What is the Current carryin capacity of steel wire armoured?
The current carrying capacity of steel wire armored cable depends on factors such as the size of the conductor, the insulation type, installation method, and ambient temperature. Typically, steel wire armored cables are available in various sizes and ratings to suit different applications and requirements. It is essential to consult the manufacturer's specifications or relevant standards for accurate information on the current carrying capacity of a specific steel wire armored cable.
How do you calculate weight of PVC insulation on cables?
By multiply current supply and voltage
Booster cables - what is the difference in use between copper cald aluminum and 100 copper wire?
It depends on some factors which are not mentioned in the question. The main difference between 100% copper wire and copper clad aluminum is that IF they are the same diameter, then the copper will carry and stand up to more electrical current than the aluminum. If the diameter of the aluminum cables have been upgraded in size, to match the current carrying capacity of the normal copper cables, then the only remaining difference is that copper withstands much more bending and coiling beforethe metal begins to "work harden," and some of the individual wire strands begin to break. In other words, the copper stands up to use better than aluminum. When buying booster cables, read the lables, and make sure that the maximum number of Amps, for which the aluminum cables are capable of carrying, is equal to or greater than the highest rated copper cables. Therefore, IF the copper clad aluminum cables are rated for the same current carrying capacity as copper cables, then there is NO difference in use between the two types.
When nonmetallic-sheathed cables are bunched or bundled together for distances longer than 24in 600mm what happens to their current-carrying ability?
Increases
