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What is the voltage source of a circuit having a resistance of 16 ohms and drawing a current of 4.3 amperes?
Wiki User
∙ 13y ago
According to ohms law...
V=I * R
So from the given values
V = 4.3*16 = 68.8 Volts
Wiki User
∙ 13y ago
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A circuit breaker is dual function. The only time it will trip is if it senses a fault current that is rated higher than the breaker rating (short circuit). The other trip condition is if the circuit is overloaded and is drawing a current higher than the breaker rating. On breakers that protect motor feeders the breaker has to be rated 250% higher than the motors full load amperage. If the breaker has lots of use and is used for a switch being manually turned off and on will weaken the trip value of the breaker. If you have access to, or know an electrician, a clamp on amp meter on the conductor that the breaker feeds will tell you what is happening. Clamp the line and turn on the load to see exactly what the current is. If, like you say, the breaker is properly rated and the current is within the breaker limits then change out the breaker for a new one.
Distinguish between op amp and differential amplifier?
Look up "op amp" on wikipedia, there is a good drawing near the bottom right. An op amp contains a differential amplifier as the first stage, but has multiple following stages that provide amplifier near ideal characteristics of high input resistance and low output resistance (it can drive more current than a single dif amplifier stage).
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How is the current in the circuit related to the resistance of the metal?
Your question is a perfect, shining example of a case in which a drawing is virtually indispensable. With a drawing, I would have some clue regarding the nature of "the current", "the circuit", and "the metal" of which you speak. Without a drawing, about the best I can tell you is that the current, expressed in Amperes, in any series circuit is numerically equal to the quotient of the potential difference between the ends of the circuit, expressed in volts, divided by the sum of the resistances of every dissipative element in the circuit, expressed in ohms.
What is the voltage of a small electric heater if the heater is drawing 12 amperes and has a resistance of 10 ohms?
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Why are the equations for working out the current in a parrel circuit inverse?
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How do you convert 2.2kVA to amps?
You can't convert kVA (kilovolt.amps) to current (amps) unless you know the source voltage and/or load resistance (ohms) which is drawing the current from the source. If you know the voltage in kilovolts, you just divide the kilovolt.amps figure by the number of kilovolts and the result is the current in amperes. If you know both source voltage and load resistance you can use Ohm's Law to get the current: I = V / R In words, Ohm's law is: Current (amps) = Voltage divided by Resistance (ohms)
Ideal universal high resistance voltmeter?
The ideal, or theoretical, voltmeter has infinite resistance, which means that, at any measured voltage, there is no current through the voltmeter. In the practical world, this is impossible, but there are high resistance voltmeters that minimize the error introduced by drawing a current from a circuit. A typical digital voltmeter has 10 to 20 megohms of resistance, and there are high performance versions that can have thousands of megohms of resistance, or more.
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There is a short circuit somewhere in the electrical system.
The drawing of an electrical circuit is called?
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How many volts would I have with one amp and 6 ohms?
You need to know the current flow through the circuit as it is now, or the resistance of the circuit to be able to determine this. If loading is very small (you're not drawing much current), you can set up a voltage divider so you get 1 volt across one resistor; this will waste electricity, so I don't suggest it if that is a serious concern. The resistors must be sized small relative to the current load to avoid causing problems with the circuit.
How do you test a car fuse?
You can use a multimeter set to resistance. It should show 0 resistance or full scale deflection on an analogue meter, if intact. You can also use a small lamp (drawing less current than the fuse) connect it to the battery with a wire, including the fuse in circuit. If the lamp lights, the fuse is Ok.
Assume a device draws 50ma of current and 150vdc across it what is its resistance?
Ohm's law: Voltage = Current times Resistance Solve: Resistance = Voltage divided by Current So, a device drawing 50ma with 150V has a resistance of 150 / 0.05, or 3000 ohms. p.s. Since power is volts times amps, that device is dissipating 7.5 watts.
Is the potential difference across an electric circuit with no element drawing current from it the same at every pt?
there should not be any diff.because
