In this situation, to calibrate a transmitter you need a power circuit and communicator circuit. The Hart communicator used in the calibration process is connected to the power source circuit in parallel. The power source circuit is the one that has ammeter, 250 Ohm resistor, and power source all connected in series. As the transmitter sends output mA, it creates volt drop across the 250 Ohm resister. Let's say the volt drop across the resistor was 1 Volt.
Now, back to the Hart communicator. It is a load, meaning there will be a volt drop across the Hart communicator. Since it is in parallel with the power circuit, it is also parallel with the resistor. So, the 1 volt drop across the 250 Ohm resistor will also make 1 volt drop across the Hart communicator. Technically speaking, the 1 volt drop across the Hart communicator is only true if its resistor is also 250 Ohm. However, it does NOT matter what voltage drop is in the Hart communcator. It only sees the "relative" voltage drop changes to measure the changes in transmitter outputs.
V = irv = (0.5)(250)v = 125
250 AD is later than 250 BC. Translation: 250 years after christ is later than 250 years before christ/
Yes. The equivalent resistance of resistors in parallel is written as 1/Req=1/R1+1/R2+1/R3+... which, in this case, would be 1/Req=1/1000+1/1000+1/1000+1/1000=0.004. This means that Req=1/0.004=250Ohms.
The GCF of 125 and 250 is 125. Since 125 is a factor of 250, it is automatically the GCF.
LCM of 20 and 250 is 500.
We use the 250 ohms with the power supply because the internal resistance of a DC power supply is insufficient to develop a resistance.
250 = 2x5x5x5
Freezing and boiling points of water.
V = irv = (0.5)(250)v = 125
Borosilicate glassware such as Pyrex is recommended for heating solids to high temperatures like 250 degrees Celsius. This type of glassware can withstand thermal shock and has a high resistance to heat, making it suitable for heating applications. Be sure to check the specific heat resistance limits of the particular glassware you are using to ensure it can safely handle the temperature.
2 x 53 = 250
250 = 21 x 53
It is: 2*53 = 250
5 megohms
250 125,2 25,5,2 5,5,5,2
2 x 53 = 250
To find the resistance needed in series with the 250 ohms inductive reactance to give a total impedance of 400 ohms, we use the Pythagorean theorem for the impedance triangle in series circuits. Given the inductive reactance (X) = 250 ohms, total impedance (Z) = 400 ohms, and resistance (R) = unknown, we have R² + X² = Z². Substituting the values, we get R = √(Z² - X²) = √(400² - 250²) = √(160000 - 62500) = √97500 ≈ 312.5 ohms. Therefore, approximately 312.5 ohms of resistance should be connected in series with the 250 ohms inductive reactance to achieve a total circuit impedance of 400 ohms.