Yes. The equivalent resistance of resistors in parallel is written as 1/Req=1/R1+1/R2+1/R3+... which, in this case, would be 1/Req=1/1000+1/1000+1/1000+1/1000=0.004. This means that Req=1/0.004=250Ohms.
The power will be the product of the square of the current and the resistance of the load. The fact that the circuit is a parallel circuit is irrelevant to this question.P = I2R = 0.032 x 1000 =0.9 W
Well, first of all, it's the current that's "going through" the wire, not the voltage.The voltage is just the difference in pressure between the two ends, and that'swhat makes the current want to go through it, towards the lower pressure. Butwe understood what you meant in the question.From Ohm's Law, [ I = E/R ] . (Current = voltage divided by resistance.)I = (10)/(5) = 2 amperes.You might not want to try this at home. The power dissipated by the wire isP = I2 R = (2)2 (5) = 20 watts.That's quite a bit of power for a piece of wire or a common resistor to dissipate.The little round resistors with the color stripes that you see everywhere arerated 1/4 watt, 1/2 watt, or 1 watt. One of those will pop if it tries to radiate20 watts, and a piece of wire with 5-ohms will glow a nice hot bright red color.
Current (I) = Voltage (V) / Resistance (Ohms) I = V/R = 50/1000 = 50 milliamperes or 50 mA
One. Measure the load resistance. Divide by five. Use that as the added series resistance. (For 1000 ohm load, add 200 ohms in series.) Note that this answer may be wrong for situations where the load resistance changes or the current is high, as you must consider source to load rejection ratio and power consumed by the added resistor. Another way is to to get a stabilised plug top power unit . Open it up and use the electronic regulator from it. Wire your 6 volts DC in place of the transformer secondary and use output as normal. The integrated three terminal regulator you are looking for is called a 7805 industry standard 1 amp regulator. ANSWER: Must know the load current first then add a series resistor to drop 1 volts with the current flow.
Diodes do not have color codes as far as I know. The "turn on" voltage is usually in the ballpark of .4 - .8 volts, and is dependent on the type of diode (germanium, etc.). You may be referring to resistors. Look up in google resistor color code, and this should help you. There will be three colored lines, two are the resistance, the third is a scaling factor. For example, if the first two colors match 82, and the third matches 3, the resistor is a 82 x 1000 = 8.2k ohm resistor. There may also be a fourth color; this denotes the resistance tolerance (1, 2, 5, or 10 percent). If the tolerance is 10%, the above example may range from 8.2k + / 1 820 ohms.
The equivalent total resistance of resistors connected in parallel is lower than the resistance of the smallest resistor. The general formula for calculating the total resistance of n resistors in parallel is Rt = 1 / (1/R1 + 1/R2 + ... 1/Rn) For two resistors in parallel, the formula simplifies to Rt = (R1 x R2) / (R1 + R2) If R1 = 10K ohms and R2 = 4.2K ohms, the total resistance of R1 in parallel with R2 is (10,000 x 4,200) / (10,000 + 4,200) = 2957.7 ohms. The total resistance is less than the smallest resistor (4.2K). For three resistors in parallel, the formula is Rt = 1 / (1/R1 + 1/R2 + 1/R3) If R1 = 100 ohms, R2 = 68 ohms, R3 = 1K ohm, the total resistance of these three resistors connected in parallel is: Rt = 1 / (1/100 + 1/68 + 1/1000) = 38.9 ohms The total resistance (38.9 ohms) is lower than the smallest resistor (68 ohms).
2003 Ohms. R = (R1 x R2)/( R1 + R2) Where R = 667 and R1 = 1000 then R2 = 2003
The power will be the product of the square of the current and the resistance of the load. The fact that the circuit is a parallel circuit is irrelevant to this question.P = I2R = 0.032 x 1000 =0.9 W
If they're connected in series the total resistance is 2000 ohms. If they're connected in parallel the resistance is 500 ohms.
.9 watts.
to convertohms to kilo ohmsjust doohms / 1000 e.g. 470ohms = .470Kohms
500 ohms. RP = 1 / summation (1 / RI)
Four 1000 ohm resistors in series have an effective resistance of 4000 ohms. Across a 4 volt voltage source, they would have a current of 1 mA, with a power dissipation of 4mW.
I don't know what the parallel circuit has to do with it. You've onlygiven me a resistor and the current through it.When 0.03A of current passes through a 1,000Ω resistor, the resistordissipates energy at the rate of 0.9 watt.
1000 ohms
What happens is that the resistance of 1100 newton is the MAXIMUM resistance. If a force of 1000 newton is applied, the actual resistance will also be 1000 newton. If a force greater than the maximum force of friction is applied, the object will start to move.
1000