When the diode is reverse biased a depletion zone is formed at the junction between the cathode and anode, that lacks current carriers (it has neither electrons or holes). Without current carriers, the diode acts as an open circuit, blocking current flow.
the current which has negative value n passes through the diode is called as diode reverse current
because that the tunnel diode is a standard pn junction diode in many respect except its highly doped pn junction so it has some characteristics in the negative resistance region another that its a standard diode
tunnel diodethe doping level of the tunnel diode is high when compared with the rectifier diodeit exhibits negative resistancerectifier diodethe doping level of rectifier diode is low when compared with the tunnel diode
I diode allows current to flow in only one direction. Therefore, if a lamp is "on" in a DC circuit, and the diode in series with the lamp is reversed, the light will be turnned off due to the diode blocking current flow (unless the voltage is above the breakdown voltage of the diode - if this is the case, the diode will fail). If this is an AC circuit, every half cycle the diode will turn on, then the next half cycle it will turn off. To your eye, the bulb will most likely appear slightly dim due to this on then off cycling. If the diode is reversed, there will be no apparent change. The difference is the half cycle the diode would have been off before reversing, it will now be on, etc.
A diode is used to stop the negative voltage swing in an AC signal, so you only get the positive portions.diode-rectifier
the current which has negative value n passes through the diode is called as diode reverse current
-- The definition of 'reverse bias' is anode negative with respect to the cathode, or negative voltage across the diode. That places the graph in negative-x territory. -- The diode simply acts as a resistor. Its unique 'diode' characteristics arise from the fact that its 'resistance' changes with different bias points, but the current through it always has the same polarity as the voltage across it. Therefor . . . -- When the voltage across it is negative, the current through it is also negative. Negative current appears on the graph in negative-y territory. -- Negative-x territory/negative-y territory is the third quadrant.
It's caused by the action of the diode. A diode conducts when its anode is positive to its cathode, or... when its cathode is negative to its anode. The above statements are saying the same thing. You circuit is applying the carrier wave to the anode, and taking output from the cathode. The diode will conduct and pass the positive peaks of the carrier from its anode to its cathode and through to the load (next component/s after the diode), but diode action will not permit conduction any time when the carrrier wave swings into negative voltage on the anode. You *could* turn the dioe around - then you would get only the *negative* peaks of the carrier wave passing through to the load.
Backward diode
A specific amount of current is allowed to flow through a diode. If the current passing through the diode exceeds this specific value, the diode gets heated and is likely to be damaged. Therefore, in the biasing circuit of a resistance which limits the current passing through the diode within its specific value is called Forward biased diode. ANSWER: A forward bias diode is just a diode that it is conducting in the forward direction. Positive to anode and negative to cathode
to get the base- emitter junction forward bias we should connect the negative of the diode with the negative of the battery and the positive of the diode with the positive of the diode so we should connect negative source in the emitter
The side of any diode that must be negative in order for the diode to conduct is the "cathode".
A: On a bridge rectifier there are two diode connected in series and in series with the load they only conduct once per cycle positive then the other two take over for the negative cycle . At the load positive the diodes will be two cathode tied together at the negative side there is two diode where the anode are tied together. either cathode anode tied together that is the ac. You cannot use an ohmmeter to check for faults this way since the load and the transformer resistance are in the way. Must remove the bridge to check it.
the rectifier is Mainly used to convert the Ac current into DC current .In rectifier there are two diodes or (4 Diode In full wave bridge rectifier )are use is to conduct the current one is connected in forward bias(i.eD1) and the other is connected in reveres bias(i.eD2). As we know that the diode is conduct the current throw it When it is connected in forward bias . now when the voltage is applied to the circuit the the AC Current is start to flow throw circuit and in Positive half cycle of Ac current the Diode is Allow the current Pass throw it and during the Negative half cycle the Diode D2 is allow the current pass throw it and in these way the rectifier rectifies positive As Well As the negative half cycle
The Banded end of diode represents Cathode.If you want the diode to be forward biased then the Cathode is made more negative than Anode.For reverse biasing of Diode (Zener Diode) The Cathode is kept positive.However the mail carrier of current in the Cathode is Electrons which are negative.
The diode is a unidirectional device it allows current to pass through it only when it is forward biased and does not allow when reverse biased when ac signal is supplied in the positive half cycle of the ac wave signal the diode will b in forward biase n in the negative half cycle it is in reverse bias .Hence it allows only the positive half cycle current to flow through it the resultant wave form will b only in one direction ,i.e,dc signal with ripples. only half of the wave is rectified hence it acts as a half wave rectifier
If you put a diode in series with an AC sine wave that goes plus and minus, it will cut off either the positive or negative portion of the waveform, depending on the direction of the diode in circuit. So in effect you have a pulse equal to one half cycle of the sine wave.