A resistor is connected in series with a practical voltage source in order to determine the current produced by the source.
* resistance increases voltage. Adding more resistance to a circuit will alter the circuit pathway(s) and that change will force a change in voltage, current or both. Adding resistance will affect circuit voltage and current differently depending on whether that resistance is added in series or parallel. (In the question asked, it was not specified.) For a series circuit with one or more resistors, adding resistance in series will reduce total current and will reduce the voltage drop across each existing resistor. (Less current through a resistor means less voltage drop across it.) Total voltage in the circuit will remain the same. (The rule being that the total applied voltage is said to be dropped or felt across the circuit as a whole.) And the sum of the voltage drops in a series circuit is equal to the applied voltage, of course. If resistance is added in parallel to a circuit with one existing circuit resistor, total current in the circuit will increase, and the voltage across the added resistor will be the same as it for the one existing resistor and will be equal to the applied voltage. (The rule being that if only one resistor is in a circuit, hooking another resistor in parallel will have no effect on the voltage drop across or current flow through that single original resistor.) Hooking another resistor across one resistor in a series circuit that has two or more existing resistors will result in an increase in total current in the circuit, an increase in the voltage drop across the other resistors in the circuit, and a decrease in the voltage drop across the resistor across which the newly added resistor has been connected. The newly added resistor will, of course, have the same voltage drop as the resistor across which it is connected.
connect 2 2ohm resistors in parallel and connect it to a series 2ohm resistor
connect a register in series with line and take the voltage at the register terminal if circuit is close.
A: To read ohms you will use it by reading in parallel and without any external voltage applied
If by capacities you mean voltages then they will add in series and have the voltage of the lower one in parallel. Putting them in parallel will generate alot of heat because the wire acts as resistor to allow the current to drop from the first battery to the second.
Divide the voltage
You could use the voltage divider rule to reduce the voltage. Using two resistors in series, the input voltage will drop across each resistor by an amount that is proportionate to the values of the resistors. If the 1st resistor is 10K and the 2nd resistor is 100K, the voltage drop across the 10K will be 10 times LESS than that of the 100K resistor. The total voltage drop across both resistors will be equal to the supplied input voltage. Work out the ratio of voltage you need from the total input voltage and use 2 resistors will that give you the same ratio. Connect the LEDs in parallel with the resistor the gives you the voltage you want. Use a MM to measure the voltage across the resistor before wiring LEDs.
It doesn't. In a series circuit, the largest voltage drop occurs across the largest resistor; the smallest voltage drop occurs across the smallest resistor.
The resistor with the most resistance.
The rule for voltage across each resistor in a series circuit is that the total voltage supplied by the source is equal to the sum of the voltage drops across each resistor. In a parallel circuit, the voltage across each resistor is the same and equal to the source voltage.
fully charged.
It depends on where and how the resistor is placed in a circuit. A string of series resistors will split the voltage across all them depending on their values. All of the resistors in parallel will have the same voltage across all of them no matter what their resistance is.
if you want to find the current (in amperes) through the resistor then connect a ammeter in series with the resistor.
A: If you know the total resistance and total voltage then you know total current flow for the circuit, this current will be same for every resistor in series however the voltage drop will change for each resistor . So measuring the voltage drop across the resistor in question and divide by the total current will give you the resistor value.
ummmmm... put it in series.
Connect a variable resistance across DC source (fixed ends of variable resistor or Rheostat) and take decreased DC output across its one fixed terminal and other variable terminal of variable resistor. Other method is connect variable resistor in series with DC output and load, vary the resistance and take decreased DC voltage as required.
Assuming galvanometer has zero or negligible internal resistance. If u connect resistor R>>RL(Load resistance) and connect it parallel to RL, it will hardly cause any change in voltage across load resistance. Suppose small current Ig goes through galvanometer. Since galvanometer have zero internal resistance, Voltage across RL = Voltage across R = IgR