The danger of a 120V socket with reversed polarity is that some appliances are designed to minimized the chance of a user coming into contact with the hot terminal of the line. This is done by polarizing the plug, making one blade wider than the other, the narrow blade being hot. In a lamp fixture, for instance, the hot side would connect to the center pin, while the neutral side would connect to the shell. The user reaching in to unscrew or screw in the bulb might touch the shell, but if that is neutral and not hot, the risk is minimized.
Another example of reversed polarity is reversed neutral and ground, which is dangerous because the ground conductor is not insulated and is therefore not rated to carry operating current.
Even more dangerous, is reversed hot and ground, which would electrify the frame of an appliance, creating an electrocution hazard.
Any electrician making one of these types of wiring errors should go to jail, and at minimum, should lose their license. Any non-electrician making one of these types of wiring errors may have to learn to hard way, such as by killing someone, that things electrical are best left to licensed electricians. By the way, in most US jurisdictions, if a wiring error causes a fire, the fire marshal will report that to the insurance company and the insurance company will revoke the fire insurance on the dwelling - that should make anyone stop and think about what they are doing.
12 watts
I imagine it depends where you live... 120v in USA, and 230v in UK & spain.
No. Some carry batteries internally (handhelds), and some are wired for 120v power (base stations).
A 120V household electrical outlet supplies 12 watts of powerwhen the current is 0.1 Ampere (and the power factor is 100%).
Simply put, 1.6 Amps, or for that matter any number of Amps (which is current), has nothing in and of itself, to do with Watts (which is power).In any circuit, there are three fundamental units of electrical properties - voltage (E), current (A), and resistance (R). In addition, there's the related unit of power (which are Watts[W]). In any circuit, knowing any two of the four will allow determining the third and forth. The fundamental rule used is called "Ohm's law" which states that the voltage across any circuit is proportional to it's resistance, and the current through it and is usually written as:E = I x R or simply E = IROne important detail is that V is commonly used instead of E. So E = I x R is the same as V = I x R. But using "E" is more proper (and stands for the formal name for voltage, "electromotive force" also sometimes abbreviated as "EMF").One other essential equation is W = I x E.Using these two equations will answer your question but you must have at least one more unit in addition to Amps, either power, resistance, or voltage.Without knowing another unit in addition to your current of 1.6A, the question cannot be answered.As an example, let's take a 100W light bulb which runs on 120V.Using the relationships shown above, we can calculate that for this bulb, it's current is I = W / E = 100W / 120V = 0.833A.It's resistance then, is E / I = 120V / 0.833A = 144 Ohms.So given it's power (W) and voltage (E) we have all four quantities:E = 120 Volts, R = 144 Ohms, I = 0.8 Amps, W = 100 WattsNote that combining and rearranging the two equations for E & W (this requires pretty basic algebra and won't be detailed here. Just the equivalent equations will be shown), it can be shown that any two values can be used to derive all four. All the combinations are thus:Given I and W:E = W / I = 100W / 0.833 Amps = 120V and,R = W / I^2 = 100W / 0.833^2 = 144 OhmsGiven R and W:E = SQRT(W x R) = SQRT(100 x 144) = 120V and,I = SQRT(W / R) = SQRT(100 / 144) = 0.8333AGiven E and R:W = E^2 / R = 14400 / 144 = 100W and,I = E / R = 120 / 144 = 0.8333AGiven E and I:W = E x I = 120 x 0.8333 = 100 Watts and,R = E / I = 120 / 0.8333 = 144 OhmsGiven I and R:E = I x R = 0.8333 x 144 = 120V and,W = I^2 x R = 0.6944 x 144 = 100 Watts
You don't, at least, not legally.
yes
It is 120V
100 Volts
No, the cord ends have different configurations to prevent this sort of thing from happening.
Household is 120/240 volts at 60Hz. The average wall socket is 120v 60Hz.
See discussion page for more.
The average air compressor uses only about 120v. Which is the average house socket. Thus using about 400 Watts of power.
I think I understand what you are asking. 3-phase motors usually are equipped with a starter or contactor, since all 3 hot wires need to be switched. The control voltage that runs the starters is 120V, because it's safer and also 120V switches and relays are cheaper. You would have a 480-120V transformer (called a control transformer) in the starter box to provide the 120V "control voltage". So the arrangement you describe would have two contactors, with two phases reversed between them. Energize one, and the motor runs forward. Energize the other, and it runs reverse. The switch sends 120V to each of the contactors, which are equipped with 120V coils.
No. If you plug something that needs 24 volt into a 120v socket you will probably ruin your device.
Yes. As long as the voltage is designed for the lamp and the socket and fixture can handle the heat (from the rated power in watts), you can. You will probably find that the socket or connector for this lamp is different than the one intended.
Yes. The bulb will be slightly dimmer, but will last much longer. Most 145V bulbs are intended to be used in 120V exit signs. The reason for the higher voltage rating on the bulb is because it will last a long, long time when used at 120V.