Want this question answered?
372.48 nano joule
(300,000,000 meters per second) / (750,000 waves per second) = 400 meters per wave
Wavelength = (speed) divided by (frequency) =300,000,000 meters per second / 820,000 = 365.6 meters (rounded)-- 1,199.5 feet (rounded)-- 0.227 mile (rounded)
107.1 MHz has higher energy photons. The photon energy increases directly proportional to frequency. However if the station operating on 90.5 MHz transmitter's power is 1.184 times or higher than that of the station operating on 107.1 MHz transmitter's power, then the 90.5 MHz signal will have higher energy because the additional photons makeup the difference. The total energy in electromagnetic radiation is the product of the energy per photon and the number of photons (i.e. amplitude of the wave) in the radiation.
The radio spectrum for communications spans approximately from 150 kHz to 26 MHz. The visible light frequency range is at least 400 THz. No contest -- visible light is at least 15 million times higher in frequency. Energy = Planck's constant * frequency. Hence visible light carries a higher energy.
680 KHz: λ (wavelength) = about 0.2739 miles and photon energy is 2.8122488E-09 electron volts.
372.48 nano joule
(300,000,000 meters per second) / (750,000 waves per second) = 400 meters per wave
the energy of a photon is h times f
The amount of energy in a photon of light is proportional to the frequency of the corresponding light wave.... frequency of the electromagnetic radiation of which the photon is a particle.
The energy of a photon depends on it's frequency
Wavelength = (speed) divided by (frequency) =300,000,000 meters per second / 820,000 = 365.6 meters (rounded)-- 1,199.5 feet (rounded)-- 0.227 mile (rounded)
A packet of light energy is called a photon.
The energy of the photon is 3,1631.e-19 joule.
. . . photon.
photon
The energy of the photon is the same as the energy lost by the electron