372.48 nano joule
(300,000,000 meters per second) / (750,000 waves per second) = 400 meters per wave
Wavelength = (speed) divided by (frequency) =300,000,000 meters per second / 820,000 = 365.6 meters (rounded)-- 1,199.5 feet (rounded)-- 0.227 mile (rounded)
107.1 MHz has higher energy photons. The photon energy increases directly proportional to frequency. However if the station operating on 90.5 MHz transmitter's power is 1.184 times or higher than that of the station operating on 107.1 MHz transmitter's power, then the 90.5 MHz signal will have higher energy because the additional photons makeup the difference. The total energy in electromagnetic radiation is the product of the energy per photon and the number of photons (i.e. amplitude of the wave) in the radiation.
The radio spectrum for communications spans approximately from 150 kHz to 26 MHz. The visible light frequency range is at least 400 THz. No contest -- visible light is at least 15 million times higher in frequency. Energy = Planck's constant * frequency. Hence visible light carries a higher energy.
680 KHz: λ (wavelength) = about 0.2739 miles and photon energy is 2.8122488E-09 electron volts.
372.48 nano joule
(300,000,000 meters per second) / (750,000 waves per second) = 400 meters per wave
The energy of a photon is inversely proportional to its wavelength. This means that as the wavelength increases, the energy of the photon decreases. Conversely, as the wavelength decreases, the energy of the photon increases.
A packet of light energy is called a photon.
The energy of a photon depends on it's frequency
A photon in a quantum has electromagnetic energy.
Wavelength = (speed) divided by (frequency) =300,000,000 meters per second / 820,000 = 365.6 meters (rounded)-- 1,199.5 feet (rounded)-- 0.227 mile (rounded)
The energy of a photon emitted from an atom is determined by the energy difference between the initial and final energy levels of the atom. The energy of the photon is directly proportional to this difference in energy levels. If the energy levels are farther apart, the emitted photon will have higher energy, whereas if the levels are closer together, the photon will have lower energy.
The relationship between photon frequency and energy is direct and proportional. As the frequency of a photon increases, its energy also increases. This relationship is described by the equation E hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency of the photon.
Since the energy of a photon is inversely proportional to its wavelength, for a photon with double the energy of a 580 nm photon, its wavelength would be half that of the 580 nm photon. Therefore, the wavelength of the photon with twice the energy would be 290 nm.
The wavenumber of a photon is inversely proportional to its energy. This means that as the wavenumber increases, the energy of the photon decreases, and vice versa.