Radio frequency energy causes a heating affect. You can get RF burns if you touch or get really close to a wire carrying RF energy. With powers below 100 watts and normal wire insulation, RF burns are extremely unlikely. Since RF currents flow in the surface of a conductor (your skin), an RF burn is not the same as a burn from a 100 Watt soldering iron (for example).
If you position your antenna feeders and antennas out of reach of prying hands, you will be safe.
The instantaneous transmitter power will peak at 170 watts, but will bottom out at 30 watts, at intervals that correspond to peaks and valleys of the audio waveform with the maximum amplitude. The transmitter power during quiet intervals, as well as the long-term average, is 100 watts.
In Amateur Radio, PEP stands for Peak Envelope Power. This is the power of the radio wave at the top and bottom of each of it's cycles. For example, if the PEP of a wave is 100 Watts, then at the top of the wave the power is exactly 100 Watts. At the bottom of the wave, things get a little bit weirder, as the power is -100 Watts. I know it's a little hard to wrap your brain around. At the exact middle of the wave, the power is 0 watts.
Not legally, no.
Watts
Four watts out of the box, which is the legal limit set for CB radios by the FCC.
while we worry about the 0.5 watts radiation of a cell phone, a walkie talkie can normally generates a radio power of up to 5 watts. which is more harmful?
The strength of radio transmissions are expressed in "watts of power", not in voltage. Transmission strength might be weak (eg., 20 watts for my small amateur transmitter) or quite strong (eg., 50,000 watts for WSM in Nashville, Tenn.). OK: For there to be "watts of power" there must be voltage and current. Watts are voltage times current. So what is a typical voltage range of an HF transmission? This information would be helpful if one is buying a knife switch to disconnect an antenna from a transmitter. The switches are rated by their voltages. Knowing the voltage range of the signal sent from an HF transmitter would help to know if a given knife switch is capable. In the previous question, I asked specifically if anyone know the voltage. Of course transmissions are expressed in watts. But there is also a voltage range. Sorry for my slow reply -- been on vacation trip. I doubt that the application of ohms law is so simple at radio frequencies. The impedance of a tuned antenna varies along the length of the wire therefore, I would expect that the voltage might also vary. In any case, I would not want to be connecting or disconnecting the antenna while "hot". I would expect there would be a risk of personal injury and damage to the transmitter. When I had an active "ham" rig I would turn off the transmitter and 'only then' switch the antenna to my receiver. Jack
The instantaneous transmitter power will peak at 170 watts, but will bottom out at 30 watts, at intervals that correspond to peaks and valleys of the audio waveform with the maximum amplitude. The transmitter power during quiet intervals, as well as the long-term average, is 100 watts.
Radio waves are energy. Electromagnetic energy to be exact. The amount of energy a radio wave has will depend on the amount of power the transmitter has, the amount of amplification, the quality of the cable connecting it to the antenna and finally the antenna. The amount of energy is usually measured in watts.
In Amateur Radio, PEP stands for Peak Envelope Power. This is the power of the radio wave at the top and bottom of each of it's cycles. For example, if the PEP of a wave is 100 Watts, then at the top of the wave the power is exactly 100 Watts. At the bottom of the wave, things get a little bit weirder, as the power is -100 Watts. I know it's a little hard to wrap your brain around. At the exact middle of the wave, the power is 0 watts.
An amateur radio operator is one who can do anything legal with radio communications, but is not paid to do them.Some hams have been very successful at putting up ham radio satellites into orbit, the first of which was the OSCAR series in the early 1960's.(OSCAR = Orbiting Satellite Carrying Amateur Radio.)My ham friend and I became somewhat proficient at reflecting radio communications from mountains, the Moon, and so forth. (He did the Moon-bounces 'cause it is too expensive for me!) But, Hey, I had a nice, tall mountain 5 miles away that did splendid work in reflecting my measly 10 watts of VHF radio signals to much farther than if I had simply aimed the beam antenna toward the city I was trying to 'Hit'.An amateur can usually become a professional.
20 Watts
it has 400 watts
One million watts
The answer you need is found in "Ohms Law." It is expressed like this: Current = watts divided by volts Watts = Volts multiplied by current Volts = Watts divided by current. I recommend you look into the hobby of Amateur Radio and put your knowledge of electronics to a fun use. My wife and I are both 'hams' and love the hobby!
Radio waves are energy. Electromagnetic energy to be exact. The amount of energy a radio wave has will depend on the amount of power the transmitter has, the amount of amplification, the quality of the cable connecting it to the antenna and finally the antenna. The amount of energy is usually measured in watts.
A small battery AM or FM radio uses as little as 3 v at 10 mA, that is 0.03 Watts. A typical DAB radio might used 6 v at 250 mA, which is 1.5 Watts, or 40-50 times as much.