because TTL have a bias input setup to eliminate noise therefore the output will follow the logic one input if left open
JFET = junction field-effect transistor. The transistor design is to restrict/control the current in the channel by expanding or contracting the depletion region, hence the channel cross-section, with a gate signal. The gate is the junction in JFET, compared with using oxide in an MOSFET.
if its a brand new amp use the high level input wiring if you purchased it used or if it does't have high level input you can buy an adapter for it at an audio shop best buy or even walmart
Use a voltmeter with a high input impedance and measure at the source the voltage.
Trouble code P0103 means:Mass or volume circuit high input
Not sure if this is still relevant, and I thought it was a sample, but Logic's "The Dream" uses these lyrics
the pullup or pull down resistance in the diode logic gate makes it a high output resistance device.If u try to drive another diode logic gate with it the output voltage of the first gate will be affected by the resistance in the second gate.A diode logic gate should always drive a high input resistance input.
1. NAND gate is used to invert the input A (by connecting A to both inputs). 2. NAND gate used to invert B the same way 3. Now put A' and B' into into a third NAND gate. The output will be (A'B')' which is equivalent to A+B.
NOR - has two or more inputsinverter - only has one input, so that input is all inputs
Short both the inputs, if '0' is given as the input output will be '1' and if '1' is given as a input the output will be '0'
A LOW-ACTIVE gate input means that the gate's output is activated or enabled when the input signal is at a low voltage level (typically near 0 volts). In digital logic circuits, this characteristic is often seen in components like NAND and NOR gates. For example, a LOW-ACTIVE NAND gate will produce a high output unless all its inputs are low, while a LOW-ACTIVE NOR gate will produce a high output only when all its inputs are low. This behavior is essential for designing logic circuits that respond to specific input conditions.
Short the inputs together. Logic: A High input, with the inputs shorted together, will be H+H at the input side of the NAND gate, therefore resulting in a low output. A Low input, with both inputs shorted together, is L+L for inputs, resulting in a High output. Also, a NOR gate can be used in exactly the same way.
A NOT gate, also known as an inverter, is a fundamental logic gate in digital electronics that outputs the opposite value of its input. If the input is high (1), the output will be low (0), and vice versa. It performs logical negation, making it essential for constructing more complex logic circuits and performing various computations. In symbolic form, a NOT gate is often represented by a triangle pointing to a small circle, indicating the inversion.
The digital logic gate that inverts the incoming signal is called a NOT gate. It outputs a high signal (1) when the input is low (0) and vice versa. This gate is fundamental in digital circuits, as it allows for the negation of binary values. The NOT gate is sometimes represented by a triangle pointing to a small circle in circuit diagrams.
It's a "quad, 2 input nor gate". To understand the significance of a "nor" gate, you need to understand a little about digital logic. An "or" gate takes 2 or more digital inputs and if either is "on", the output will be on. (asserted high). A "nor" gate inverts the output of the "or" gate, meaning that when either of the outputs are "on", the output will be "off" (asserted low). The two input part of the description just indicates that it only accepts two inputs. So, simply stated: If either (or both) input(s) of a quad, 2 input nor gate is (are) asserted high, the output will be low. If both inputs are off (low), the output will be high.
The output of the AND gate is high when both inputs are high because that is the definition of an AND gate. (Ouput is true ONLY WHEN Input A AND Input B are true.)
One way to make an eight input AND gate out of transistors... Start with one transistor, NPN. Ground the emitter. Connect the collector to Vcc with a resistor. Connect the base to Vcc through two resistors, picked to drive the transistor into saturation. The input of that stage is the junction of the two resistors. If you ground that input, the transistor cuts off, and the collector goes high. Unground the input, and the collector goes low. OK. Now you have an inverter. Build eight of them, but only use one collector resistor, and tie all of the collectors together. If any one input is high, the output is low. If all inputs are low, the output is high. OK. Now you have an 8 input negative logic NAND gate. Follow it up with another inverter stage, reversing the output. OK. Now you still have an 8 input NAND gate, with the output high true. If you want the inputs to be high true also, connect each one to an inverter. This will use 17 transistors, and you will have an 8 input positive logic AND gate.
A 4-input majority logic gate outputs a high signal (1) if the majority of its inputs (at least 3 out of 4) are high (1). The truth table for a 4-input majority gate includes 16 rows, reflecting all possible combinations of the four inputs (A, B, C, D). The output is 1 for the following input combinations: 1110, 1101, 1011, 0111, 1111, and any other combination that has at least three 1s. The output is 0 for combinations with fewer than three 1s.