answersLogoWhite

0

23 volts across 470 ohms will dissipate about 1.1 watts.

Power equals voltage squared divided by resistance.

User Avatar

Wiki User

15y ago

What else can I help you with?

Related Questions

How many ohms in 800 watts?

To calculate the resistance in ohms, you also need to know the voltage. The formula to find the resistance in ohms is R = V^2 / P, where R is the resistance in ohms, V is the voltage, and P is the power in watts.


In Canada how many people are there per doctor?

470.... apparently :P


If you have 500 watts at 4 ohms how many watts do you have at 8 ohms?

250 watts approximatelyI assume you have a constant voltage supply. According to P=V^2/R => P*R=V^2, you have a 44.7 volt supply. If you change Resistance to 8 ohms, P=44.7^2/8 => P=250 watts.


Resistance of a 110V 100W lamp is?

The formula you are looking for is, R = Volts (squared)/Watts.


What is the difference between 6 ohms and 8 ohms?

Though it is tempting to say the difference is 2 ohms (8 ohms minus 2 ohms equals 6 ohms), lets look at some things. The 6 ohms is 3/4ths the resistance of the 8 ohms. If the resistances are loads, the 6 ohm load will draw 1/3rd more current than the 8 ohm load. The 8 ohm load will draw 3/4ths as much as the 6 ohm load. Those are some differences between 6 ohms and 8 ohms.


What are the electrical formulas for Volts Watts Current Resistance Ampere and Ohms?

Watts = Volts x Amps x Powerfactor Volts = Amps x Ohms Note: Power Factor is one for resistance loads and decreases toward zero for loads like motors. watts=VI=v*v/R=I*I*R volt=IR=square root of PR=P/I Ampere=V/R=P/V=square root of P/R ohms=V/I=V*V/P=P/I*I


A 12 volts power supply is connected across two resistors R1 120 ohms and R2 470 ohms in series Calculate the potential difference across each when the negative terminal of supply is earthed explain?

Earthing of the negative terminal is a common practice and will not affect the potential across the resistors in the circuit. Calculating this is simple Ohm's Law. For a series circuit: R(total) = R1 + R2 + R3....... Rn In this case: Rt = 120 + 470 = 590 ohms Per ohms law E = I x R. We need to find the current flowing throught the circuit so: I = E/R = 12 / 590 = .0203 amps or 20.3 milliamps The potential across an individual resistor is calculated again by E = I x R So for R1 (120 ohms): E1 = I x R1 = .0203 x 120 = 2.44 V So for R2 (470 ohms): E2 = I x R2 = .0203 x 470 = 9.54 V For a check E = E1 + E2 = 2.44 + 9.54 = 11.98 The .02 difference is due to the use of significant figures.Another AnswerEarthing the negative terminal will have no affect on the potential DIFFERENCE across each resistor. 'Potential' exists at a single point. 'Potential difference' exists between two points.


What is 468 rounded to the nearest ten?

It is 470.


What is 81 percent of 470?

81% of 470= 81% * 470= 0.81 * 470= 380.7


WHAT IS 30 percent OF 470?

30% of 470= 30% * 470= 0.3 * 470= 141


How do you calculate the amount of current that will go through the resistor a 12 volt battery a resistor of 470 ohms?

Ohm's Law: Current is voltage divided by resistance.12 volts divided by 470 ohms is 25.5 milliamperes.Power is voltage times current, so power in this case would be 12 volts times 25.5 milliamperes, or 0.306 watts. As a result, you need at least a one half watt resistor, and I would prefer a one watt resistor, because it is going to get a bit warm, and a margin of safety is always a good thing. This is particularly true when you consider tolerances, such as the battery actually putting out 13 or 14 volts and the resistor being on the low side, at 470 - 10%, or 423 ohms. (0.463 watts - too close to one half watt for comfort)


Calculate the resistor in a circuit having 12V source voltage and power dissipation of 10 W?

0.069444444444444444444444444444444444 ohms. P/E^2=R. P = power in watts. E = electricity in volts. R = resistance in ohms.