500L
The milliliter and the cubic centimeter are equal volumes.
A 2.5 liter jug is equivalent to 2500 ml. To find out how many 250 ml cups can be filled from this jug, you simply divide the total volume of the jug by the volume of each cup. In this case, 2500 ml divided by 250 ml equals 10 cups. Therefore, you can fill 10 cups with a volume of 250 ml each from a 2.5 liter jug.
250l
Yes
Provided that the substance you're referring to is a liquid or a solid (which I'll assume it is, judging by the large mass) you would calculate the density by dividing the mass (475g) by the volume (250cc) giving you a measurement in grams per cubic centimeter. In this case...475g/250cc=1.9g/ccThe only difference for a gas is that the density can be calculate in grams/liter instead. in which case the equation would be:475g/.250L = 1860g/L Which is almost twice the density of water @ 5 degrees Celsius.
The milliliter and the cubic centimeter are equal volumes.
A 2.5 liter jug is equivalent to 2500 ml. To find out how many 250 ml cups can be filled from this jug, you simply divide the total volume of the jug by the volume of each cup. In this case, 2500 ml divided by 250 ml equals 10 cups. Therefore, you can fill 10 cups with a volume of 250 ml each from a 2.5 liter jug.
No, it is .25 tons. If you mean liters of water. 1 ton = 1000KG 1000L = 1000KG 250L = 250KG ∴ 250KG = .25ton
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1 litre = 1000 millilitres so you could pour 4 glasses.
Two differences are the LC has an O ring at the cylinder base in addition to the regular gasket, and the LC regular base gasket is about a quarter the cost of the L model base gasket.
If you need to make just 100mL, then you need 1 tenth of a liter that is 5M. If you were to make 1L of 5 molar NaCl, you would need 5 times the molar mass of NaCl (58.44g/mol) dissolved in 1L of water. Thus for 1L of a 5M solution you need 5 * 58.44g, or 292.2 grams of NaCl. However, since we only want 100mL, which is 1/10 of a Liter, we also only need 1/10 the amount of NaCl, or 292.2 / 10, which is 29.22g. So, measure out 29.22g NaCl, and dissolve completly in a volume less than 100mL, say 80mL, then bring the final volume up to 100mL. You now have 100mL of a 5M NaCl solution.
The key formula for solving a dilution problem is M1V1=M2V2 (alternately, MAVA=MBVB) where concentration is M (measured in Molars, a unite of concentration-->Molars=moles solute/Liters solution) and the volume of solution is V. M1V1 represents the inital conditions (pre-dilution), and M2V2 denotes the final conditions (post-dilution). Plug in the three values you know to find the fourth value, which you are solving for. Ex. 750mLs of a 0.5 M NaC2H3O2 solution is diluted with 250mL of H2O. What is the new concentration of NaC2H3O2? Answer: (0.5M)x(.750L)=(MB)x(.750L+.250L) 0.375ML=(MB)x(1L) MB=0.375M
250ml is less than 250l Because ml is mili liter that is less