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What is the molarity of a solution prepared by dissolving 20.00g CaCl2 in enough water to make 1.00L of solution?
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
Calculate the molarity of a solution of glycerol made by dissolving 43.000 mL glycerol at 15 degrees C in enough water to make 200.00 mL of solution?
To find the molarity, we need to first calculate the number of moles of glycerol using its density at 15°C, which is 1.260 g/mL. Then, convert the mass of glycerol to moles using its molar mass of about 92.09 g/mol. Finally, divide the moles by the total volume of the solution in liters (200.00 mL = 0.200 L) to get the molarity.
The molarity of a 5 percent solution of NH3 in water?
The molarity of a 5% solution of NH3 in water depends on the density and molecular weight of NH3. Without this information, it is not possible to calculate the molarity.
What is the molarity of a solution that has 6 mol of CaCl2 in 3 kg of water?
The molarity is 2 mol/L.
What Word would you use to descirbe sugar dissolving into water?
"Soluble" is the word that describes sugar dissolving into water.
What is the molarity of a solution made by dissolving 23.4g of sodium sulphate in enough water to make up a 125ml solution?
To find the molarity, first calculate the number of moles of sodium sulphate using its molar mass. Sodium sulphate's molar mass is 142.04 g/mol. Next, divide the number of moles by the volume in liters (125 ml = 0.125 L) to get the molarity. This will give you the molarity of the sodium sulphate solution.
What is the molarity of a solution made by dissolving 3.09 moles of Nacl in 1.50 L of solution?
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
What is the molarity of a solution prepared by dissolving 20.00g CaCl2 in enough water to make 1.00L of solution?
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
What is the molarity of a solution made by dissolving 2 moles of NaOH in 10 kg of water?
The molarity of the solution would be approximately 0.2 M. This is calculated by first converting the mass of water to volume (10 kg is roughly equivalent to 10 L), then using the formula Molarity = moles of solute / volume of solution in liters.
What is the Molarity of a solution made from dissolving 53.6grams of calcium carbonate in 0.94 liters of water?
It doesn't exist - calcium carbonate is limestone/marble - its insoluble
What is molarity of a solution made by dissolving 2 moles of NaOH in 6 kg of water?
To find the molarity, we first need to convert the mass of water to volume using the density of water. Given the density of water is approximately 1000 g/L, 6 kg of water is equivalent to 6000 g or 6 L. Next, calculate the molarity using the formula Molarity (M) = moles of solute / liters of solution. In this case, 2 moles of NaOH in 6 L of water gives a molarity of 0.33 M.
How 0.1M NaOH form?
0.1 M NaOH is prepared by dissolving sodium hydroxide (NaOH) pellets or flakes in water to make a 0.1 molar solution. This means there are 0.1 moles of NaOH dissolved in 1 liter of water. The molarity of the solution is calculated using the formula: Molarity = moles of solute / liters of solution.
What is the molarity of a solution made by dissolving 2 moles of Na OH in 6 kg of water?
6 kg = 6000 grams and density of water = 1.00 grams/milliliters. 1.00 g/ml = 6000 grams/X ml = 6000 ml which = 6 liters ======================== Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/6 Liters = 0.3 M NaOH solution -----------------------------
What is the molarity of the solution made by dissolving 22.4 g of LiClO4 3H2O in 225 mL of water?
First, calculate the molar mass of LiClO4 3H2O. Then, convert 22.4 g to moles using the molar mass. Next, determine the molarity by dividing the moles of LiClO4 3H2O by the volume of solution in liters (225 mL = 0.225 L).
What is the molarity of a solution prepared by dissolving 1.56 grams of gaseous HCl in enough water to make 26.8 mL of solution?
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
Calculate the molarity of a solution of glycerol made by dissolving 43.000 mL glycerol at 15 degrees C in enough water to make 200.00 mL of solution?
To find the molarity, we need to first calculate the number of moles of glycerol using its density at 15°C, which is 1.260 g/mL. Then, convert the mass of glycerol to moles using its molar mass of about 92.09 g/mol. Finally, divide the moles by the total volume of the solution in liters (200.00 mL = 0.200 L) to get the molarity.
What is the concentration of a solution made by dissolving 20 g of KOH in 150 mL of water?
20 g/150 mL = 0.13 g/mL = 130 g/L
