there are no co efficents infront of any of the reactants or products
Strontium chloride and sodium sulfate will react to form strontium sulfate and sodium chloride. This reaction is a double displacement reaction where the cations and anions of the two compounds switch partners.
When strontium chloride and sodium sulfate are mixed, a double displacement reaction occurs. The strontium cations (Sr2+) combine with sulfate anions (SO4 2-) to form strontium sulfate (SrSO4), which is insoluble and precipitates out of the solution as a solid. Sodium cations (Na+) combine with chloride anions (Cl-) to form sodium chloride (NaCl), which remains dissolved in the solution.
You would start by simply writing your reactants and products out, noting this is a double replacement reaction. BaCl2 + Li2SO4 -----> BaSO4 + LiCl Then you would need to go back and balance the equation. Note in the above that there are two chloride ions on the left but only one on the right. This can be balanced by placing a coefficient of 2 in front of LiCl. BaCl2 + Li2SO4 -----> BaSO4 + 2LiCl This is now a balanced equation.
The chemical equation for the reaction between aqueous strontium sulfide (SrS) and aqueous copper sulfate (CuSO4) is: SrS + CuSO4 → SrSO4 + CuS Strontium sulfate (SrSO4) and copper sulfide (CuS) are the products of this double displacement reaction.
The exchange reaction between sulfuric acid (H2SO4) and strontium hydroxide (Sr(OH)2) results in the formation of strontium sulfate (SrSO4) and water (H2O). This reaction can be represented by the chemical equation: H2SO4 + Sr(OH)2 → SrSO4 + 2H2O. In this reaction, the hydrogen ions (H+) from sulfuric acid combine with the hydroxide ions (OH-) from strontium hydroxide to form water, while the strontium ions (Sr2+) from strontium hydroxide combine with the sulfate ions (SO4 2-) from sulfuric acid to form strontium sulfate.
The balanced equation for Iron (III) chloride reacting with copper (II) sulfate is: 2FeCl3 + 3CuSO4 → Fe2(SO4)3 + 3CuCl2
Strontium chloride and sodium sulfate will react to form strontium sulfate and sodium chloride. This reaction is a double displacement reaction where the cations and anions of the two compounds switch partners.
The balanced chemical equation for barium chloride (BaCl2) reacting with potassium sulfate (K2SO4) is: BaCl2 + K2SO4 -> BaSO4 + 2KCl. This reaction forms barium sulfate (BaSO4) and potassium chloride (KCl).
Because strontium sulfate is much less soluble in water than strontium chloride, sodium chloride, or sodium sulfate, this reaction is: Na2SO4 (aq) + SrCl2 (aq) => 2 NaCl (aq) + SrSO4 (s).
The balanced equation for the reaction between barium sulfate (BaSO4) and calcium chloride (CaCl2) is BaSO4 + CaCl2 -> BaCl2 + CaSO4. This reaction forms barium chloride (BaCl2) and calcium sulfate (CaSO4) as products.
This equation is BaCl2 (aq) + Na2SO4 (aq) -> 2 NaCl (aq) + BaSO4 (s).
When strontium chloride and sodium sulfate are mixed, a double displacement reaction occurs. The strontium cations (Sr2+) combine with sulfate anions (SO4 2-) to form strontium sulfate (SrSO4), which is insoluble and precipitates out of the solution as a solid. Sodium cations (Na+) combine with chloride anions (Cl-) to form sodium chloride (NaCl), which remains dissolved in the solution.
Ba2+ + [2Cl- + 2Na+] + SO42---> BaSO4 + [2Cl- + 2Na+]Ba2++ SO42- --> BaSO4
K2SO4(aq) + SrI2(aq)=SrSO4(aq) + 2kI(aq)
The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4
BaCl2(aq) + Na2SO4 (aq) ------> BaSO4(s) + 2NaCl(aq)
Ooh. Somebody doesn't like doing their chem homework. Luckily I just happened to do that exact same equation. 1 BaCl2 +1 Na2S --> 2 NaCl(Salt! :D) +1 BaS