You would start by simply writing your reactants and products out, noting this is a double replacement reaction.
BaCl2 + Li2SO4 -----> BaSO4 + LiCl
Then you would need to go back and balance the equation. Note in the above that there are two chloride ions on the left but only one on the right. This can be balanced by placing a coefficient of 2 in front of LiCl.
BaCl2 + Li2SO4 -----> BaSO4 + 2LiCl
This is now a balanced equation.
Strontium chloride and sodium sulfate will react to form strontium sulfate and sodium chloride. This reaction is a double displacement reaction where the cations and anions of the two compounds switch partners.
When strontium chloride and sodium sulfate are mixed, a double displacement reaction occurs. The strontium cations (Sr2+) combine with sulfate anions (SO4 2-) to form strontium sulfate (SrSO4), which is insoluble and precipitates out of the solution as a solid. Sodium cations (Na+) combine with chloride anions (Cl-) to form sodium chloride (NaCl), which remains dissolved in the solution.
there are no co efficents infront of any of the reactants or products
The chemical equation for the reaction between aqueous strontium sulfide (SrS) and aqueous copper sulfate (CuSO4) is: SrS + CuSO4 → SrSO4 + CuS Strontium sulfate (SrSO4) and copper sulfide (CuS) are the products of this double displacement reaction.
To calculate the amount of lithium nitrate needed to make lithium sulfate, first determine the molar masses of the two compounds. Then, use stoichiometry and the balanced chemical equation for the reaction between lithium nitrate and lithium sulfate to find the quantity needed. This will depend on the stoichiometry of the reaction between lithium nitrate and lithium sulfate.
Complete ionic equation is:2Li^+(aq) + SO4^2-(aq) = Sr^2+(aq) + 2Cl^-(aq) ==>2Li^+(aq) + 2Cl^-(aq) + SrSO4(s)
The ionic equation for the reaction between lithium sulfate (Li2SO4) and strontium chloride (SrCl2) is: 2Li+ + SO4^2- + Sr^2+ + 2Cl- → SrSO4 + 2LiCl
Because strontium sulfate is much less soluble in water than strontium chloride, sodium chloride, or sodium sulfate, this reaction is: Na2SO4 (aq) + SrCl2 (aq) => 2 NaCl (aq) + SrSO4 (s).
Strontium chloride and sodium sulfate will react to form strontium sulfate and sodium chloride. This reaction is a double displacement reaction where the cations and anions of the two compounds switch partners.
When strontium chloride and sodium sulfate are mixed, a double displacement reaction occurs. The strontium cations (Sr2+) combine with sulfate anions (SO4 2-) to form strontium sulfate (SrSO4), which is insoluble and precipitates out of the solution as a solid. Sodium cations (Na+) combine with chloride anions (Cl-) to form sodium chloride (NaCl), which remains dissolved in the solution.
there are no co efficents infront of any of the reactants or products
Examples of salts: sodium chloride, uranyle nitrate, potassium acetate, strontium iodide, ammonium phosphate, lithium fluoride, magnesium sulfate, boron fluoride
The chemical equation for the reaction between aqueous strontium sulfide (SrS) and aqueous copper sulfate (CuSO4) is: SrS + CuSO4 → SrSO4 + CuS Strontium sulfate (SrSO4) and copper sulfide (CuS) are the products of this double displacement reaction.
This word equation is incorrect because it does not follow the law of conservation of mass. The equation should be: calcium chloride plus magnesium sulfate yields barium sulfate plus magnesium chloride.
The chemical formula for sodium carbonate is Na2CO3 and for lithium sulfate is Li2SO4. When they react, the balanced chemical equation is: 2Na2CO3 + Li2SO4 → Na2SO4 + Li2CO3
The balanced equation for the formation of lithium sulfate is: 2LiOH + H2SO4 → Li2SO4 + 2H2O
lithium carbonate + sulfuric acid = lituim sulfate + water + carbon dioxide