Correct.
The mass of 7,346 moles of Ca(OH)2 is 544,3 g.
2 moles of Ca and 4 moles of OH
The reaction between calcium oxide (CaO) and water (H2O) to form calcium hydroxide (Ca(OH)2) is a synthesis reaction. In this type of reaction, two or more reactants combine to form a single product. The equation can be represented as: CaO + H2O → Ca(OH)2. This reaction is also classified as a hydration reaction, as water is added to a solid compound.
CaOH2 is a base because calcium is compounded with hydroxide, rather than hydrogen. Most if not all acids' names begin with 'H', while most if not all bases' names end with 'OH'.
To find the mass of Ca(OH)₂ in 500 mL of a 0.00500 M solution, first calculate the number of moles of Ca(OH)₂: [ \text{Moles} = \text{Molarity} \times \text{Volume (in L)} = 0.00500 , \text{mol/L} \times 0.500 , \text{L} = 0.00250 , \text{mol} ] Next, calculate the mass using the molar mass of Ca(OH)₂ (approximately 74.09 g/mol): [ \text{Mass} = \text{Moles} \times \text{Molar Mass} = 0.00250 , \text{mol} \times 74.09 , \text{g/mol} \approx 0.1852 , \text{g} ] Thus, there are approximately 0.185 grams of Ca(OH)₂ in 500 mL of a 0.00500 M solution.
Nope... it is not.
Calcium hydroxide.
Calcium hydroxide.
Calcium hydroxide is written as Ca(OH)2 because the hydroxide ion (OH-) is a polyatomic ion composed of one oxygen atom and one hydrogen atom. In the compound, there are two hydroxide ions associated with one calcium ion, which is why it is written as Ca(OH)2 and not CaOH2.
CaCl2 and H2O
In one mole of this solution, there are seven moles of H2O.
Ca(OH)2 and Na2O
The mass of 7,346 moles of Ca(OH)2 is 544,3 g.
2 moles of Ca and 4 moles of OH
Calcium Hydroxide, or CaOH2, is a base. Generally compounds containing hydroxyl groups and metals will act as bases in reaction.
http://wiki.answers.com/Q/Calculate_for_a_solution_formed_by_adding_4.80ml_of_0.130_M_KOH_to_19.0ml_of_7.6x102_M_of_CaOH2"
The molecular weight of Ca(OH)2 (calcium hydroxide) is approximately 74.09 g/mol.