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What is the percentage of water to the nearest tenth in this compound for NiSO 7H2O?
The compound NiSO4·7H2O consists of one NiSO4 molecule and seven water molecules. The percentage of water can be calculated by dividing the molar mass of water by the molar mass of the whole compound, and then multiplying by 100. This results in about 37.2% water in NiSO4·7H2O.
What is the percentage of water to the nearest tenth of niso4 and 7h2o?
44.9
How much moles of OH liberate during the borax hydrolysis?
B4O7^2- + 7H2O = 4H3BO3 + 2OH- B4O7^2- : 2OH- = 1:2 Therefore there are twice the number of moles of Hydroxide ions produced as there are Borate ions
What is there compound name for 7H2O?
The compound name for 7H2O is heptahydrate.
Calculate the percent of water of FeSO47H20?
1. Find the molar mass (MM) of the substances.MM FeSO4 = 151.91g+MM 7H2O = 126.11gMM FeSO4 x 7H2O = 278.02g2. Find the percent water of hydrate.Divide the mass of water by the mass of the hydrate; multiply result by 100%.126.11g278.02g x 100%Percent water of FeSO4 * 7H2O is 45.36%.Finding Molar Mass# atoms Element A x atomic mass Element A = Mass A# atoms Element B x atomic mass Element B = Mass B... etc.Add up all the mass values for the substance and you have the molar mass of the substance.
What is the equation when ferrous sulphate crystal is heated?
When ferrous sulfate heptahydrate crystals (FeSO4·7H2O) are heated, they undergo a dehydration reaction to form anhydrous ferrous sulfate (FeSO4) and water vapor (H2O). The chemical equation for this reaction is: FeSO4·7H2O(s) → FeSO4(s) + 7H2O(g)
What is the chemical equation for the dehydration of magnesium sulfate?
The chemical equation for the dehydration of magnesium sulfate (MgSO4) is as follows: MgSO4·7H2O + Heat => MgSO4 + 7H2O A link is provided below for more information.
What is the decomposition equation for Epsom salt?
The decomposition equation for Epsom salt (magnesium sulfate heptahydrate) is: MgSO4·7H2O -> MgSO4 + 7H2O. When heated, Epsom salt loses its water molecules, leaving behind anhydrous magnesium sulfate.
What is the molecular weight of 7H2O?
Ah, the molecular weight of 7H2O, or water, is about 126.14 grams per mole. Isn't that just a lovely number? Remember, understanding the molecular weight helps us appreciate the beauty and harmony of chemistry.
What is manesium sulfate heptahydrate as a formula?
The formula for magnesium sulfate heptahydrate is MgSO4·7H2O. This compound contains one magnesium (Mg) ion, one sulfate (SO4) ion, and seven water (H2O) molecules.
What is the cation of MgSO4 plus 7H2O?
The cation of MgSO4·7H2O is Mg^2+ (magnesium ion).
What mass of MgSO4 7 H2O is required to prepare 300 mL of a 0.529 M MgSO4 solution?
To prepare a 0.529 M MgSO4 solution, you first need to calculate the moles of MgSO4 required for 300 mL (0.300 L) of solution: Moles of MgSO4 = Molarity × Volume = 0.529 mol/L × 0.300 L = 0.1587 mol. Next, since MgSO4·7H2O is the hydrated form, its molar mass is approximately 246.47 g/mol. Therefore, the mass needed is: Mass = Moles × Molar Mass = 0.1587 mol × 246.47 g/mol ≈ 39.06 g of MgSO4·7H2O.
