Yes, due to the energy of photons/electromagnetic particles being determined by the equations below:
E= hv=hc(1/v)= hc/wavelength.
Where E= energy, v= frequency in Hz, h= Planck's constant, c= speed of light
Electrons have a very short wavelength, and a very high frequency, thus they have much more energy than a beam of light.
Well, first of all, protons don't make light. I think you mean 'photons'. A photon of ultraviolet light carries more energy than a photon of visible light, because it has a higher frequency / shorter wavelength.
he duble hockey sticks no.
im 75% positive that it does penetrate deeper than infrared radiation.
Each photon of blue light has more energy than a photon of any other color, because the blue ones have the highest frequency.
The energy of a photon is determined by its frequency, not its intensity. Violet light has a higher frequency than red light, which means each violet photon carries more energy. Thus, even though the red beam may be more intense, the individual photons in the violet beam can still impart more energy to the ejected electron.
The energy of a photon is inversely propotional to its wavelength. The wavelength of a blue photon is less than that of a red photon. That makes the blue photon more energetic. Or how about this? The energy of a photon is directly proportional to its frequency. The frequency of a blue photon is greater than that of a red photon. That makes the blue photon more energetic. The wavelength of a photon is inversely proportional to its frequency. The the longer the wavelength, the lower the frequency. The shorter the wavelength, the higher the frequency.
Yes it does.
The violet light has more energy than the red light. Red light is lower on the electromagnetic spectrum, meaning it has a lower frequency (or longer wavelength). You'll recall the colors of the rainbow as red, orange, yellow, etc., and these are the colors going up the frequency spectrum. Photons higher on the spectrum are higher in frequency and energy.
Violet light has a shorter wavelength and higher frequency than red light. Energy of a photon is directly proportional to its frequency, so violet light has more energy than red light.
Well, first of all, protons don't make light. I think you mean 'photons'. A photon of ultraviolet light carries more energy than a photon of visible light, because it has a higher frequency / shorter wavelength.
No, it could not. A blue photon carries more energy than a red photon, since the blue photon's frequency is higher. That means one red photon wouldn't deliver enough energy to the atom to give it the energy to emit a blue photon.
When light is bluer, it means it has a higher frequency. Each photon carries energy, and the energy of a photon is directly proportional to its frequency. Therefore, in bluer light, each photon contains higher energy compared to redder light.
A photon of violet light has higher energy than a photon of yellow light. This is because violet light has a higher frequency and shorter wavelength compared to yellow light. The energy of a photon is directly proportional to its frequency, according to the equation E=hf, where E is energy, h is Planck's constant, and f is frequency.
he duble hockey sticks no.
Theoretically, gamma rays are distinguished by their source, not by the amount of energy each photon carries, so it's not really possible to answer.In practice, most gamma rays have far more energy per photon than visible light.
im 75% positive that it does penetrate deeper than infrared radiation.
Each photon of blue light has more energy than a photon of any other color, because the blue ones have the highest frequency.