he duble hockey sticks no.
The lowest possible energy state for a photon is when it has no energy, which corresponds to a frequency of zero.
The smallest energy drop of an electron produces red light. When an electron transitions to its lowest energy level, it emits a photon with the least energy, corresponding to the red wavelength of light.
Infrared waves are shorter than radio waves and longer than visible light waves.
Radio waves have the least energy per photon among the types of electromagnetic radiation. Their longer wavelengths correspond to lower frequencies, resulting in lower energy according to the equation E = hf, where E is energy, h is Planck's constant, and f is frequency. Consequently, radio waves carry significantly less energy compared to higher energy radiation like gamma rays or X-rays.
There is no such thing as "long energy" or "short energy". The electromagnetic spectrum is:Radio waves; microwaves; infrared; visible light; ultraviolet; x-rays; gamma rays. In this list, going from left to right: * The energy per photon increases. * The frequency increases. * The wavelength decreases. Thus, for instance, gamma rays have the LARGEST energy per photon; the LARGEST frequency; and the SHORTEST wavelength.
No, radio waves have the lowest frequency on the electromagnetic spectrum, but they do not necessarily have the lowest energy per photon. The energy of a photon is determined by its frequency, with higher frequencies corresponding to higher energies. Therefore, photons from higher frequency waves such as gamma rays have higher energy per photon compared to radio waves.
More energy per photon than visible light, if that's what you mean.
The radio spectrum for communications spans approximately from 150 kHz to 26 MHz. The visible light frequency range is at least 400 THz. No contest -- visible light is at least 15 million times higher in frequency. Energy = Planck's constant * frequency. Hence visible light carries a higher energy.
Nope. Radio waves have a long wavelength, which causes them to carry little energy. For future questions about energy and waves, use the formula E=h(c/lambda). E is the energy of the wave, h is plank's constant, c is the speed of light (3x10^8), and lambda is the frequency. Have fun! ^_^
Visible light and radio waves are both two types of the same radiation (electromagnetic waves). The difference is that visible light has a higher frequency; a higher energy per photon; and a smaller wavelength.
The particle that carries radiant energy is the photon. Photons are elementary particles that travel at the speed of light, carrying energy in the form of electromagnetic radiation. They are responsible for phenomena like light, heat, and other forms of radiant energy.
The measure of a photon's energy is its frequency or equivalently, its wavelength. This is determined by the amount of energy carried by the photon, corresponding to the electromagnetic spectrum as visible light, radio waves or X-rays depending on the energy level.
Visible light has shorter wavelengths than microwaves. Microwaves, which might be considered the highest energy radio waves, have a longer wavelength (and a lower frequency) than visible light.
To calculate the energy of a photon, you can use the formula E = hc/λ, where E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength. Plugging in the values for h (6.626 x 10^-34 J s), c (3 x 10^8 m/s), and the wavelength (220 m) will give you the energy of the radio photon.
The relationship between electromagnetic energy (photon energy) and wavelength is determined by two constants - the speed of light and Planck's constant. Photon energy (in Joules) is equal to the speed of light (in metres per second) multiplied by Plancks constant (in Joule-seconds) divided by the wavelength (in metres). E = hc/wavelength where: E is photon energy h is Planck's constant = 6.626 x 10-34 Js c is the speed of light = 2.998 x 108 m/s This relationship shows that short wavelengths (e.g. X-rays) have high photon energies while long wavelengths (e.g. Radio waves) have low photon energies.
The lowest possible energy state for a photon is when it has no energy, which corresponds to a frequency of zero.
The smallest energy drop of an electron produces red light. When an electron transitions to its lowest energy level, it emits a photon with the least energy, corresponding to the red wavelength of light.