1.8x10^20 / 6.022 x 10^23 = 2.99 x 10^(-4) = .000299 moles
Also rounded could be 3.0 x 10^-4.
To find the number of moles of silver, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mole. The number of moles can be calculated using the formula: [ \text{moles} = \frac{\text{number of atoms}}{\text{Avogadro's number}} = \frac{3.35 \times 10^{22}}{6.022 \times 10^{23}} \approx 0.0556 \text{ moles}. ] Thus, the sample contains approximately 0.0556 moles of silver.
The answer is 0,465 moles.
To find the mass of 4.50 x 10²² atoms of silver (Ag), first, determine the molar mass of silver, which is approximately 107.87 g/mol. Using Avogadro's number (6.022 x 10²³ atoms/mol), calculate the number of moles: ( \frac{4.50 \times 10^{22} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mol}} \approx 0.0747 \text{ moles} ). Finally, multiply the number of moles by the molar mass: ( 0.0747 \text{ moles} \times 107.87 \text{ g/mol} \approx 8.05 \text{ g} ). Thus, the mass of 4.50 x 10²² atoms of silver is approximately 8.05 grams.
To find the number of uranium atoms in 0.70 moles, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Multiplying the number of moles by Avogadro's number gives: (0.70 , \text{moles} \times 6.022 \times 10^{23} , \text{atoms/mole} \approx 4.21 \times 10^{23} , \text{atoms}). Thus, there are approximately (4.21 \times 10^{23}) uranium atoms in 0.70 moles.
To find the number of moles of nickel atoms in (8.00 \times 10^9) Ni atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mole. The calculation is as follows: [ \text{Moles of Ni} = \frac{8.00 \times 10^9 \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \approx 1.33 \times 10^{-14} \text{ moles} ] Thus, there are approximately (1.33 \times 10^{-14}) moles of nickel atoms in (8.00 \times 10^9) Ni atoms.
1 mole of silver contains 6.022 X 10^23 atoms 62 moles of silver contains 3.73 X 10^25 atoms of silver
To find the number of moles of silver, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mole. The number of moles can be calculated using the formula: [ \text{moles} = \frac{\text{number of atoms}}{\text{Avogadro's number}} = \frac{3.35 \times 10^{22}}{6.022 \times 10^{23}} \approx 0.0556 \text{ moles}. ] Thus, the sample contains approximately 0.0556 moles of silver.
The answer is 0,465 moles.
To find the mass of 4.50 x 10²² atoms of silver (Ag), first, determine the molar mass of silver, which is approximately 107.87 g/mol. Using Avogadro's number (6.022 x 10²³ atoms/mol), calculate the number of moles: ( \frac{4.50 \times 10^{22} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mol}} \approx 0.0747 \text{ moles} ). Finally, multiply the number of moles by the molar mass: ( 0.0747 \text{ moles} \times 107.87 \text{ g/mol} \approx 8.05 \text{ g} ). Thus, the mass of 4.50 x 10²² atoms of silver is approximately 8.05 grams.
One mol is 6.02214179×1023 so about 3*10-4 (3 times ten to the minus 4) moles
To find the number of uranium atoms in 0.70 moles, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Multiplying the number of moles by Avogadro's number gives: (0.70 , \text{moles} \times 6.022 \times 10^{23} , \text{atoms/mole} \approx 4.21 \times 10^{23} , \text{atoms}). Thus, there are approximately (4.21 \times 10^{23}) uranium atoms in 0.70 moles.
To find the number of moles of nickel atoms in (8.00 \times 10^9) Ni atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mole. The calculation is as follows: [ \text{Moles of Ni} = \frac{8.00 \times 10^9 \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \approx 1.33 \times 10^{-14} \text{ moles} ] Thus, there are approximately (1.33 \times 10^{-14}) moles of nickel atoms in (8.00 \times 10^9) Ni atoms.
avogadro's constant is the number of atoms (or molecules, as in the case of compounds) contained in a mole of a substance. roughly, then, in 4 moles of gold there are 4 x 6.02 x 10 to the 23rd power atoms or two septillion, four hundred eight sextilllion atoms. (2,408,000,000,000,000,000,000,000) see also: http://en.wikipedia.org/wiki/Avogadro_constant
To find the number of moles of nitrogen in (1.61 \times 10^{24}) atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Calculating the moles: [ \text{Moles of nitrogen} = \frac{1.61 \times 10^{24} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \approx 2.68 \text{ moles} ] Thus, there are approximately 2.68 moles of nitrogen in (1.61 \times 10^{24}) atoms.
To find the number of moles in (1.63 \times 10^{24}) atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Divide the number of atoms by Avogadro's number: [ \text{moles} = \frac{1.63 \times 10^{24}}{6.022 \times 10^{23}} \approx 2.71 \text{ moles}. ] Thus, there are approximately 2.71 moles in (1.63 \times 10^{24}) atoms.
To find the number of atoms in 2.5 moles of magnesium, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Multiplying 2.5 moles by Avogadro's number gives you: [ 2.5 , \text{moles} \times 6.022 \times 10^{23} , \text{atoms/mole} \approx 1.51 \times 10^{24} , \text{atoms}. ] Therefore, there are about (1.51 \times 10^{24}) atoms of magnesium in 2.5 moles.
To find the number of atoms in 1.2 moles of uranium (U), you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Multiply the number of moles by Avogadro's number: [1.2 , \text{moles} \times 6.022 \times 10^{23} , \text{atoms/mole} \approx 7.23 \times 10^{23} , \text{atoms}.] Thus, there are approximately (7.23 \times 10^{23}) atoms in 1.2 moles of uranium.