1.8x10^20 / 6.022 x 10^23 = 2.99 x 10^(-4) = .000299 moles
Also rounded could be 3.0 x 10^-4.
To find the number of moles of silver, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mole. The number of moles can be calculated using the formula: [ \text{moles} = \frac{\text{number of atoms}}{\text{Avogadro's number}} = \frac{3.35 \times 10^{22}}{6.022 \times 10^{23}} \approx 0.0556 \text{ moles}. ] Thus, the sample contains approximately 0.0556 moles of silver.
The answer is 0,465 moles.
To find the mass of 4.50 x 10²² atoms of silver (Ag), first, determine the molar mass of silver, which is approximately 107.87 g/mol. Using Avogadro's number (6.022 x 10²³ atoms/mol), calculate the number of moles: ( \frac{4.50 \times 10^{22} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mol}} \approx 0.0747 \text{ moles} ). Finally, multiply the number of moles by the molar mass: ( 0.0747 \text{ moles} \times 107.87 \text{ g/mol} \approx 8.05 \text{ g} ). Thus, the mass of 4.50 x 10²² atoms of silver is approximately 8.05 grams.
To find the number of moles of nickel atoms in (8.00 \times 10^9) Ni atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mole. The calculation is as follows: [ \text{Moles of Ni} = \frac{8.00 \times 10^9 \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \approx 1.33 \times 10^{-14} \text{ moles} ] Thus, there are approximately (1.33 \times 10^{-14}) moles of nickel atoms in (8.00 \times 10^9) Ni atoms.
To find the number of moles of nitrogen in (1.61 \times 10^{24}) atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Calculating the moles: [ \text{Moles of nitrogen} = \frac{1.61 \times 10^{24} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \approx 2.68 \text{ moles} ] Thus, there are approximately 2.68 moles of nitrogen in (1.61 \times 10^{24}) atoms.
1 mole of silver contains 6.022 X 10^23 atoms 62 moles of silver contains 3.73 X 10^25 atoms of silver
To find the number of moles of silver, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mole. The number of moles can be calculated using the formula: [ \text{moles} = \frac{\text{number of atoms}}{\text{Avogadro's number}} = \frac{3.35 \times 10^{22}}{6.022 \times 10^{23}} \approx 0.0556 \text{ moles}. ] Thus, the sample contains approximately 0.0556 moles of silver.
The answer is 0,465 moles.
One mol is 6.02214179×1023 so about 3*10-4 (3 times ten to the minus 4) moles
avogadro's constant is the number of atoms (or molecules, as in the case of compounds) contained in a mole of a substance. roughly, then, in 4 moles of gold there are 4 x 6.02 x 10 to the 23rd power atoms or two septillion, four hundred eight sextilllion atoms. (2,408,000,000,000,000,000,000,000) see also: http://en.wikipedia.org/wiki/Avogadro_constant
To find the number of atoms in 2.5 moles of magnesium, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Multiplying 2.5 moles by Avogadro's number gives you: [ 2.5 , \text{moles} \times 6.022 \times 10^{23} , \text{atoms/mole} \approx 1.51 \times 10^{24} , \text{atoms}. ] Therefore, there are about (1.51 \times 10^{24}) atoms of magnesium in 2.5 moles.
H2O is water. One mole of water contains 2 moles of hydrogen atoms. Therefore, 10.7 moles of water contain 21.4 moles of hydrogen atom.
Avogadro's number times 5.6 (or about 33.6 times ten to the 23rd power.
2.01x10^22 atoms x 1 mole/6.02x10^23 atoms = 0.0334 moles
There are (6.023 \times 10^{23}) atoms in 1 mole of any substance (Avogadro's number). Therefore, there are (1.004 \times 6.023 \times 10^{23} \approx 6.05 \times 10^{23}) atoms in 1.004 moles of bismuth.
The number of moles is 0,528.
There are (~6.022 \times 10^{23}) atoms in one mole of sulfur. Therefore, in 3 moles of sulfur there are (~3 \times 6.022 \times 10^{23} \approx 1.807 \times 10^{24}) atoms of sulfur.